Question

您好我试图通过ajax从jsp调用servlet，并从servlet返回两个数据。但是面对结果数据的一些问题。

两个pono podt在输出端组合在一起。如何拆分相同以获得正确的数据。

＆＃13;

$(document).ready(function() {
	$('#grn').blur(function() {
		$.ajax({
			url : 'callserv0',
			type: 'POST',
			data : {
				grnno : $('#grn').val()
			},
			success : function(data) {
				alert("new");
				$('#pono').val(data);
				$('#podt').val(data);
				return false; 
			}
		});
	});
});

＆＃13;

<script src="http://code.jquery.com/jquery-1.10.2.js"
	type="text/javascript"></script>
<script src="js/app-ajax.js" type="text/javascript"></script>
</head>
<body>
<form>
		Receipt number: <input type="text" id="grn" />
		PO number: <input type="text" id="pono" />
		PO Date : <input type="text" id="podt" />
		<input type="button" id="find" value="Find" />
	</form>
</body>

＆＃13;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class callserv0 extends HttpServlet {
	private static final long serialVersionUID = 1L;

	protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException 
	{
		//response.setContentType("text/html"); 
		//PrintWriter out= response.getWriter();
		//out.println("i am in callserv0");	
		
		String grn = request.getParameter("grnno");
				
		String pono = grn;
		
		String podt = "12/12/12";
		
		response.setContentType("text/plain");
		response.getWriter().write(pono);
		response.getWriter().write(podt);
	}

}

＆＃13;

enter image description here

Answer 1

在将值写入响应时，可以使用逗号（，）等分隔符。然后使用JavaScript方法 split（）

var str = "123,2/21/2017";
var res = str.split(",");
console.log(res[0]);
console.log(res[1]);

通过ajax将多个数据从servlet传递给jsp

1 个答案: