如何使用CONCAT搜索表数据以及php中的条件？

Question

我试图根据用户登录会话变量过滤数据库中的表值 这是我的代码：

if(isset($_POST['search'])){
    $submit = $_POST['submit'];
    $query = "SELECT * FROM milkvalue WHERE userid = '$user_id', CONCAT(      `month`) LIKE '%".$submit."%' ";
    $search_result = filterTable($query);
} else {
    $query = "select * from milkvalue where userid = '$user_id'";
    $search_result = filterTable($query);
}

function filterTable($query){
    $con = new mysqli("localhost", "root", "", "milk");
    $filter_Result = mysqli_query($con,$query);
    return $filter_Result;          
}

Answer 1

您的CONCAT查询不正确。它应该是

npm install -g ionic@latest