Question

Todays_Sales表中的所有列（ID，Salesperson，Item，Type）。

我当前的查询结果显示：

ID      Salesperson     Item    Type        
---------------------------------------
75343   Mike Germain    3874    Credit          
75343   Ken Johnson     2590    Cash            
67850   Justin Anderson 6435    Check           
67850   Mike Germain    1228    Credit

我希望我的查询结果显示：

ID      Salesperson 1   Item 1  Type 1  Salesperson 2   Item 2  Type 2
----------------------------------------------------------------------
75343   Mike Germain    3874    Credit  Ken Johnson     2590    Cash
67850   Justin Anderson 6435    Check   Mike Germain    1228    Credit

Answer 1

试试这个：

WITH
input(id,salesperson,item,type) AS (
          SELECT 75343, 'Mike Germain'   ,3874,'Credit'
UNION ALL SELECT 75343, 'Ken Johnson'    ,2590,'Cash'
UNION ALL SELECT 67850, 'Justin Anderson',6435,'Check'
UNION ALL SELECT 67850, 'Mike Germain'   ,1228,'Credit'
)
-- Common Table Expression above is just for data, don't use
-- in real query
,
-- begin WITH clause with this if selecting from table
input_w_seq AS (
SELECT
  id
, ROW_NUMBER() OVER(PARTITION BY id) AS seq
, salesperson
, item
, type
FROM input
)
SELECT
  id
, MAX(CASE seq WHEN 1 THEN salesperson END) AS salesperson_1
, MAX(CASE seq WHEN 1 THEN item        END) AS item_1
, MAX(CASE seq WHEN 1 THEN type        END) AS type_1
, MAX(CASE seq WHEN 2 THEN salesperson END) AS salesperson_2
, MAX(CASE seq WHEN 2 THEN item        END) AS item_2
, MAX(CASE seq WHEN 2 THEN type        END) AS type_2
FROM input_w_seq
GROUP BY
  id
ORDER BY
  id
;

id    |salesperson_1  |item_1|type_1|salesperson_2|item_2|type_2
67,850|Justin Anderson| 6,435|Check |Mike Germain | 1,228|Credit
75,343|Mike Germain   | 3,874|Credit|Ken Johnson  | 2,590|Cash

SQL查询为每个唯一的客户ID返回一行

1 个答案: