Question

我在我的一个测试中有以下run_phase任务：

   //run_phase
   task run_phase(uvm_phase phase);
      tx_big_sml_diff_sequence tx_seq_i;
      axi_config_reg_sequence axi_seq_i;
      phase.raise_objection(.obj(this));
      for (int i = 2; i <= 9; i++) begin
                tx_seq_i = tx_big_sml_diff_sequence::type_id::create(.name("tx_seq_i"), .contxt(get_full_name()));
                axi_seq_i = axi_config_reg_sequence::type_id::create(.name("axi_seq_i"), .contxt(get_full_name()));
                axi_seq_i.transfers[0] = i;
                axi_seq_i.addr = `TX_FE_LIN_INT_ADDR;
                fork
                    begin
                       tx_seq_i.start(grb_env_i.tx_lin_int_agent_i.tx_lin_int_sequencer);   
                    end
                    begin
                       axi_seq_i.start(grb_env_i.axi_agent_i.axi_sequencer);
                    end
                join
      end
      phase.drop_objection(.obj(this));
      super.run_phase(phase);
   endtask // run_phase

其中axi_config_reg_sequence是负责配置特定reg的序列（根据给定的地址）。

我想在TX_FE_LIN_INT_ADDR旁边配置另一个reg，如何为另一个配置使用相同的序列？

Answer 1

您没有提供有关axi_config_reg_sequence实现的任何详细信息，因此我将假设addr变量自动负责在该特定地址配置寄存器。如果是这种情况，您可以再次实例化相同的序列，然后在同一个序列器上启动它，如下所示：

          tx_seq_i = tx_big_sml_diff_sequence::type_id::create(.name("tx_seq_i"), .contxt(get_full_name()));
          axi_seq1_i = axi_config_reg_sequence::type_id::create(.name("axi_seq1_i"), .contxt(get_full_name()));
          axi_seq2_i = axi_config_reg_sequence::type_id::create(.name("axi_seq2_i"), .contxt(get_full_name()));

          axi_seq1_i.transfers[0] = i;
          axi_seq1_i.addr = `TX_FE_LIN_INT_ADDR;

          axi_seq2_i.transfers[0] = `SET_THIS_VARIABLE_AS_NEEDED;
          axi_seq2_i.addr = `YOUR_OTHER_ADDRESS_GOES_HERE;

          fork
              begin
                 tx_seq_i.start(grb_env_i.tx_lin_int_agent_i.tx_lin_int_sequencer);   
              end
              begin
                 axi_seq1_i.start(grb_env_i.axi_agent_i.axi_sequencer);
                 axi_seq2_i.start(grb_env_i.axi_agent_i.axi_sequencer);
              end
          join

如何使用同一类的2个不同实例？

1 个答案: