Question

我写了下面的代码，它会导致错误：

price = item.find('span', "sx-zero-spacing'").text，此行会导致错误：AttributeError: 'NoneType' object has no attribute 'text'
它确实创建了一个名为＆＃34; scraper_data.csv＆＃34;的文件，但是，当我打开文件时，它是空的，里面没有任何数据。
此外，当我再次运行上述.py文件时，发生了另一个错误csvfile = open('scraper_data_csv', 'a') PermissionError: [Errno 13] Permission denied: 'scraper_data_csv'

请提供任何帮助或建议！谢谢！

from bs4 import BeautifulSoup
import requests
import csv

url = "https://www.amazon.com/s/?field-keywords=horse+head+mask"
headers = {'User-Agent': 'Mozilla/5.0'}

response = requests.get(url, headers = headers)

soup = BeautifulSoup(response.text, "html.parser")

items = soup.find_all("li", "s-result-item")

csvfile = open('scraper_data.csv', 'a')
writer = csv.writer(csvfile)

for item in items:
    name = item.find('h2').text
    price = item.find('span', "sx-zero-spacing'").text
    writer.writerow([name, price])

Answer 1

而不是with open，请尝试try，它会在块结束时自动关闭文件。另外，使用except / sx-zero-spacing来捕获没有from bs4 import BeautifulSoup import requests import csv url = 'https://www.amazon.com/s/?field-keywords=horse+head+mask' headers = {'User-Agent': 'Mozilla/5.0'} response = requests.get(url, headers=headers) soup = BeautifulSoup(response.text, 'html.parser') items = soup.find_all('li', 's-result-item') with open('scraper_data.csv', 'w') as csvfile: writer = csv.writer(csvfile) for item in items: try: name = item.find('h2').text price = item.find('span', 'sx-zero-spacing').text except AttributeError: continue writer.writerow([name, price])的商品。

Students Name:     Grade:
1. Ben             1
2. Cathy           1
3. Tom             1
4. Mark            1
5. Lisa            1
6. Bernard         1
7. John            2
8. Macy            2
9. Rose            2
10. Maynard        2
11. Bill           2
12. Sherlock       2

Python-CSV-writerow：发生错误

1 个答案: