PHP - Echo在if语句中什么都不做

时间：2017-03-02 03:33:43

标签： php

所以这是我到目前为止的代码，我记得如果IP匹配，则回显带有详细信息的表单，如果不回显错误消息。但由于某种原因，我无法让它工作

（需要添加更多细节，所以如果你愿意，可以忽略它） 基本上，脚本获取客户端的IP，如果IP匹配文件中的IP然后显示一些凭据，如果它没有回显错误消息或只是将一些文本回显到文本字段

   <?php


$ip = $_SERVER['REMOTE_ADDR'];

?>
<?php
/**
 * Created by PhpStorm.
 * User: test
 * Date: 02/03/2017
 * Time: 03:15 ص
 */

?>
<!DOCTYPE html>
<html lang="en">
  <head>
    <meta charset="utf-8">
    <meta name="author" content="">
    <link rel="icon" href="../../favicon.ico">

    <title>Login</title>

    <!-- Bootstrap core CSS -->
    <link href="css/bootstrap.css" rel="stylesheet">
      <link href="css/style.css" rel="stylesheet">


  </head>

  <body>

    <nav class="navbar navbar-inverse navbar-fixed-top">
      <div class="container">
        <div class="navbar-header">
          <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar">
            <span class="sr-only">Toggle navigation</span>
            <span class="icon-bar"></span>
            <span class="icon-bar"></span>
            <span class="icon-bar"></span>
          </button>
          <a class="navbar-brand" href="#">Password</a>
        </div>
        <div id="navbar" class="collapse navbar-collapse">
          <ul class="nav navbar-nav">
            <li class="active"><a href="index.php">Passwords</a></li>


          </ul>
        </div><!--/.nav-collapse -->
      </div>
    </nav>

    <div class="container">
             <form method="post" style="margin-top:100px;">
             <?php

       if($ip == "ip1" or "ip2"){

            $user = "someuser";
            $pass = "somepass";
            $pin = "somepin";
       echo "



            <div class=\"form-group\">
                <label for=\"exampleInputEmail1\">Username</label>
                <input type=\"email\" name=\"email\" class=\"form-control\" placeholder=\"Email\" value=\"$user \">
            </div>
            <div class=\"form-group\">
                <label for=\"exampleInputPassword1\">Password</label>
                <input type=\"text\" name=\"password\" class=\"form-control\" placeholder=\"Password\" value=\"$pass \">
            </div>
            <div class=\"form-group\">
                <label for=\"exampleInputPassword1\">Pin</label>
                <input type=\"text\" name=\"password\" class=\"form-control\" placeholder=\"Password\" value=\"$pin  \">
            </div>


       ";
       }
       else{
           echo "



            <div class=\"form-group\">
                <label for=\"exampleInputEmail1\">Username</label>
                <input type=\"email\" name=\"email\" class=\"form-control\" placeholder=\"Email\" value=\"  LOL \">
            </div>
            <div class=\"form-group\">
                <label for=\"exampleInputPassword1\">Password</label>
                <input type=\"text\" name=\"password\" class=\"form-control\" placeholder=\"Password\" value=\"  LOL \">
            </div>
            <div class=\"form-group\">
                <label for=\"exampleInputPassword1\">Pin</label>
                <input type=\"text\" name=\"password\" class=\"form-control\" placeholder=\"Password\" value=\"  LOL  \">
            </div>


       ";
       }

?>
</form>
    </div><!-- /.container -->


    <!-- Bootstrap core JavaScript
    ================================================== -->
    <!-- Placed at the end of the document so the pages load faster -->
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
    <script src="js/bootstrap.js"></script>

  </body>
</html>

4 个答案:

答案 0 :(得分：0)

<?php
if($ip == "ip1" or $ip =="ip2"){

    $user = "someuser";
    $pass = "somepass";
    $pin = "somepin";
}
else
{
    $user = "LOL";
    $pass = "LOL";
    $pin = "LOL";
}
?>
            <div class="form-group">
                <label for="exampleInputEmail1">Username</label>
                <input type="email" name="email" class="form-control" placeholder="Email" value="<?php echo $user; ?>">
            </div>
            <div class="form-group">
                <label for="exampleInputPassword1">Password</label>
                <input type="text" name="password" class="form-control" placeholder="Password" value="<?php echo $pass;?>">
            </div>
            <div class="form-group">
                <label for="exampleInputPassword1">Pin</label>
                <input type="text" name="password" class="form-control" placeholder="Password" value="<?php echo $pin;?>">
            </div>

或

<?php
if($ip == "ip1" or $ip =="ip2"){

    $user = "someuser";
    $pass = "somepass";
    $pin = "somepin";
}
else
{
    $user = "LOL";
    $pass = "LOL";
    $pin = "LOL";
}
echo '<div class="form-group">
                <label for="exampleInputEmail1">Username</label>
                <input type="email" name="email" class="form-control" placeholder="Email" value="'.$user.'">
            </div>
            <div class="form-group">
                <label for="exampleInputPassword1">Password</label>
                <input type="text" name="password" class="form-control" placeholder="Password" value="'.$pass.'">
            </div>
            <div class="form-group">
                <label for="exampleInputPassword1">Pin</label>
                <input type="text" name="password" class="form-control" placeholder="Password" value="'.$pin.'">
            </div>';
?>

答案 1 :(得分：0)

首先检查$ip值，

然后尝试这种格式

if($ip=='ip1'){
//code here
}else if($ip=='ip2'){
//code here
}else{
//code here
}

答案 2 :(得分：0)

我想如果我是你，我会使用像in_array()这样的原生函数在列表中搜索ip。如果你在||条款中有一堆or / if，那就太丑了。此外，您可以将ips存储在xml，json或其他外部源（如数据库）中，这样您就不必在php文件中对这些存储的值进行硬编码。

# Get the ip
$myIp = $_SERVER['REMOTE_ADDR'];
# In-php file list of ips
$listOfIps = array(
    '73.121.122.131',
    '213.22.132.11',
    '91.89.222.32'
);
# Check in the list for the user's ip
if(in_array($myIp,$listOfIps)) {
    // Do something here
}

要从外部文件中提取，它看起来像这样。我添加了一些类，使其更具人性化：

<强> /ips.json 

["73.121.122.131","213.22.132.11","91.89.222.32"]

<强>的index.php 

class FileHandler
    {
        public function getIpList()
            {
                return json_decode(file_get_contents(__DIR__.'/ips.json'),true);
            }
    }

class Admin
    {
        private $FileHandler;

        public function __construct(\FileHandler $FileHandler)
            {
                $this->FileHandler = $FileHandler;
            }

        public function ipAllowed()
            {
                $ips = $this->FileHandler->getIpList();
                $ip  = $_SERVER['REMOTE_ADDR'];
                return in_array($ip,$ips);
            }
    }

$Admin  =  new Admin(new FileHandler());
if($Admin->ipAllowed()) {
    // Do special stuff here
}
else {
    // Do regular stuff
}

答案 3 :(得分：-1)

你不能使用＆＃34;开始你的回声，然后在HTML中使用它们。这会创建一个字符串的结尾。用＆＃39;开始你的回声然后保留双引号。另外，黑曜石对于＆＃34;或＆＃34;是正确的。是||。

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