我有以下XML文件(它实际上是VS2010 dbproj文件)
<?xml version="1.0" enconding="utf-8"?>
<Project.....>
<propertyGroup>
....
</PropertyGroup>
<ItemGroup>
<Build Include = "Schema Objects\Schemas\dbo\Programmability\Stored Procedures\foo.sql>
</Build>
</ItemGroup>
</Project>
我想使用LINQ to XML来提取存储过程的所有Build元素。 我有以下代码,似乎不起作用:
var doc = XDocument.Load(filePath);
var elements = doc.Descendants("Build").Where( x => x.Attribute("Include").Value.Contains("Stored Procedure")).ToList();
提取属性值的正确方法是什么?
感谢您的回复!事实证明,在Project标签中指定了一个名称空间,我省略了它。这就是我得到0结果的原因。
答案 0 :(得分:2)
var doc = XElement.Parse(xml);
// or
var doc = XDocument.Load(path);
var q = from e in doc.Descendants("Build")
from a in e.Attributes("Include")
where a.Value.Contains("Stored Procedure")
select e;
var list = q.ToList();
P.S。这种方法不需要检查每个变量的null,例如:
var q = from e in doc.Descendants("Build")
where e != null
from a in e.Attributes("Include")
where a != null && a.Value != null && a.Value.Contains("Stored Procedure")
select e;
答案 1 :(得分:0)
一旦你修复了XML(你错过了一个结束语,并且那里有不匹配的标签),它就可以了。在LINQPad中测试
string xml =
"<Project>"+
"<PropertyGroup>" +
"</PropertyGroup>" +
"<ItemGroup>" +
"<Build Include = \"Schema Objects\\Schemas\\dbo\\Programmability\\Stored Procedures\\foo.sql\">"+
"</Build>"+
"</ItemGroup>"+
"</Project>";
var doc = XDocument.Parse(xml);
var elements = doc.Descendants("Build").Where (x => x.Attribute("Include").Value.Contains("Stored Procedure")).ToList();
elements.Dump();
结果是:
<Build Include="Schema Objects\Schemas\dbo\Programmability\Stored Procedures\foo.sql"> </Build>
如果你只是想获得价值,试试这个:
var element2 = doc.Descendants("Build").Where (x => x.Attribute("Include").Value.Contains("Stored Procedure")).Select (x => x.Attribute("Include").Value);
element2.Dump();
编辑 - 这也有效:
var element3 = doc.Descendants("Build").Select(x=>x.Attribute("Include")).Where(y=>y.Value.Contains("Stored Procedure")).FirstOrDefault().Value;