Question

我有一个名为blob的嵌套词典，如下所示：

{
"/var/log": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"},
"/opt": {"vgsize": "9.32g","vgname": "VolGroupOpt","desired_lv_size": "50"}
"/tmp": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"}
}

我需要：为每个desired_lv_size获取vgname的总和。

我将如何应对这一挑战？

我开始尝试：

set(blob.values())

可能会提取唯一的vgname。但那给了我：

TypeError: unhashable type: 'dict'

Answer 1

from collections import Counter

c = Counter()
for v in data.values():
    c[v['vgname']] += int(v["desired_lv_size"])

Answer 2

您可以执行以下操作

from collections import defaultdict

data = {
    "/var/log": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"},
    "/opt": {"vgsize": "9.32g","vgname": "VolGroupOpt","desired_lv_size": "50"},
    "/tmp": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"}
}

res = defaultdict(int)
for d in data.values():
    group = d.get("vgname")
    value = float(d.get("desired_lv_size"))
    res[group] += value

print(res)
# defaultdict(<class 'int'>, {'VolGroup': 40.0, 'VolGroupOpt': 50.0})

Answer 3

假设 desired_lv_size值是整数，这将起作用：

x={
"/var/log": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"},
"/opt": {"vgsize": "9.32g","vgname": "VolGroupOpt","desired_lv_size": "50"},
"/tmp": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"}
}

totals={}
for f, f_data in x.items():
    v=int(f_data["desired_lv_size"])
    if f_data["vgname"] in totals:
        totals[f_data["vgname"]]+=v
    else:
        totals[f_data["vgname"]]=v

for vgname, total in totals.items():
    print("{0} total={1}".format(vgname, total))

Answer 4

我会遍历字典的值并将desired_lv_size条目添加到每个vgname键入的字典中，如下所示：

vg_sizes = {}
for vg_dict in blob.values():
    size = vg_sizes.setdefault(vg_dict['vgname'], 0)
    vg_sizes[vg_dict['vgname']] = size + int(vg_dict['desired_lv_size'])

vg_sizes最终为所有'vgname'键入的词典，其值为所有'desired_lv_size'的总和。

Answer 5

blob = {
"/var/log": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"},
"/opt": {"vgsize": "9.32g","vgname": "VolGroupOpt","desired_lv_size": "50"},
"/tmp": {"vgsize": "46.27g","vgname": "VolGroup","desired_lv_size": "20"}
}
a = {}
for value in blob.values():
    if value["vgname"] in a:
        a[value["vgname"]] += int(value["desired_lv_size"])
    else:
        a[value["vgname"]] = int(value["desired_lv_size"])

a是必需的词典。

这种方法只使用一个dict来存储最终结果，没有额外的导入，也没有并发症。

Python汇总值和收集唯一值

5 个答案: