Question

我收到服务电话的回复：

var response =  "\"   {\\\"errcode\\\":1,\\\"errmsg\\\":\\\"ok\\\",\\\"data\\\":\\\"https:\\\\/\\\\/mp.weixin.qq.com\\\\/cgi-bin\\\\/showqrcode?ticket=gQH38DwAAAAAAAAAAS5odHRwOi8vd2VpeGluLnFxLmNvbS9xLzAyYTZKU1pzczJhdmUxWHZ6MzFvMTcAAgTfurtYAwQA6QcA\\\"}\""

我解码并获得了

var responseAfterDecode = decodeURI(response);

// responseAfterDecode

"{\"errcode\":1,\"errmsg\":\"ok\",\"data\":\"https:\\/\\/mp.weixin.qq.com\\/cgi-bin\\/showqrcode?ticket=gQH38DwAAAAAAAAAAS5odHRwOi8vd2VpeGluLnFxLmNvbS9xLzAyYTZKU1pzczJhdmUxWHZ6MzFvMTcAAgTfurtYAwQA6QcA\"}"

之后我解析了JSON：

var JSONAfterParse = JSON.parse(responseAfterDecode);

// JSONAfterParse =

{"errcode":1,"errmsg":"ok","data":"https:\/\/mp.weixin.qq.com\/cgi-bin\/showqrcode?ticket=gQH38DwAAAAAAAAAAS5odHRwOi8vd2VpeGluLnFxLmNvbS9xLzAyYTZKU1pzczJhdmUxWHZ6MzFvMTcAAgTfurtYAwQA6QcA"}

这看起来像一个完美的JSON。但是当我试图访问

时

JSONAfterParse.data --> undefined.

无法弄清楚出了什么问题。

Answer 1

您尝试从STRING而不是从Object访问属性，您需要使用JSON.parse(string) ...

var JSONAfterParse = '{"errcode":1,"errmsg":"ok","data":"https:\/\/mp.weixin.qq.com\/cgi-bin\/showqrcode?ticket=gQH38DwAAAAAAAAAAS5odHRwOi8vd2VpeGluLnFxLmNvbS9xLzAyYTZKU1pzczJhdmUxWHZ6MzFvMTcAAgTfurtYAwQA6QcA"}';
var ParsedJSON = JSON.parse(JSONAfterParse);
console.log(ParsedJSON.data);

Answer 2

看起来你实际上有双字符串化的JSON（JSON字符串表示的字符串表示）。这意味着在单个JSON.parse之后，您仍然会返回一个字符串（因此缺少任何data属性）。呸。但是，您可以通过再次解析JSON来解决问题：

var response =  "\"   {\\\"errcode\\\":1,\\\"errmsg\\\":\\\"ok\\\",\\\"data\\\":\\\"https:\\\\/\\\\/mp.weixin.qq.com\\\\/cgi-bin\\\\/showqrcode?ticket=gQH38DwAAAAAAAAAAS5odHRwOi8vd2VpeGluLnFxLmNvbS9xLzAyYTZKU1pzczJhdmUxWHZ6MzFvMTcAAgTfurtYAwQA6QcA\\\"}\""

var responseAfterDecode = decodeURI(response)

var jsonAfterParse = JSON.parse(JSON.parse(responseAfterDecode))

console.log(jsonAfterParse.data)

Answer 3

＆＃13;

var response =  "\"   {\\\"errcode\\\":1,\\\"errmsg\\\":\\\"ok\\\",\\\"data\\\":\\\"https:\\\\/\\\\/mp.weixin.qq.com\\\\/cgi-bin\\\\/showqrcode?ticket=gQH38DwAAAAAAAAAAS5odHRwOi8vd2VpeGluLnFxLmNvbS9xLzAyYTZKU1pzczJhdmUxWHZ6MzFvMTcAAgTfurtYAwQA6QcA\\\"}\""

var responseAfterDecode = decodeURI(response);

var js =JSON.parse(responseAfterDecode);
js = JSON.parse(js);

console.log(js.data);

＆＃13;

参考：JSON parse double quotes in string literal

JSON Parsing the string to object

无法从JSON获取数据

3 个答案: