Question

我试图在壁架随机机会游戏上编码一种行走，用户会输入他们想要下注的一定金额，然后根据他们将采取多少步骤，他们将生活或从壁架上掉下来。到目前为止，代码是FAR完成但我遇到了一个问题，我想知道是否有人可以帮我修复它。

import time
import random


class Player():
    def __init__(self,name):
        self.name = name
        self.luck = 2
        self.gold = 10

def main():
    print("Hello what is your name?")
    option = input("--> ")
    global PlayerIG
    PlayerIG = Player(option)
    start1()

def start1():
    print("Name: {}".format(PlayerIG.name))
    print("Luck: {}".format(PlayerIG.luck))
    print("Gold: {}".format(PlayerIG.gold))
    inputgold()

def inputgold():
    print("Please input how much gold you would like to play with")
    goldinput = input("--> ")
    strgold = str(goldinput)
    print("You inputted {}".format(strgold))
    if strgold <= PlayerIG.gold:
        print("You don't have enough gold")
        inputgold()
    else:
        print("Get ready to start!")
    ledge()

def ledge():
    print("You are standing on a ledge with an unknown length")
    time.sleep(1)
    choice = input("How many steps do you want to take forward? Between 1-100")
    if choice == step1:
        print("You have fallen off the ledge")
        PlayerIG.gold -= goldinput
        print("Gold: ".format(PlayerIG.gold))
    elif choice == step2:
        print("You...")
        time.sleep(1)
        print("Didn't fall off the ledge!")
        PlayerIG.gold*1.2
        print("Gold: ".format(PlayerIG.gold))
    else:
        print("You slipped off the ledge and face planted onto the side walk")
        PlayerIG.gold -= goldinput
        print("Gold: ".format(PlayerIG.gold))

def steps():
    step1 = random.randint(10,30)
    step2 = random.randint(30,50)
    step3 = random.randint(50,100)

main()

当我跑步时说：

if strgold <= PlayerIG.gold: TypeError: unorderable types: str() <= int()

我该如何解决？

Answer 1

问题在于这一行：

if strgold <= PlayerIG.gold:

这里你要比较一个字符串和一个整数。这是不可能的，您必须先将字符串转换为整数：

if int(strgold) <= PlayerIG.gold:

我没有检查你的其余代码，但我怀疑你在其他地方也可能也有类似的错误。

我的python游戏代码不起作用

1 个答案: