（存储过程）如何排序特殊序列

Question

我有一个问题如何按顺序进行排序

select * from (select @fYear as [Year],
(case when main.Description in ('Kecil', 'Tanah') then 'JK'
 else main.Description
 end) as description,

  --CardType,
  sum(case when MONTH(blue.AppliedDate) = 1 then 1 else 0 end) as Jan_Collection,
  sum(case when MONTH(blue.AppliedDate) = 2 then 1 else 0 end) as Feb_Collection,
 ...

 from tblR as main
 left join tblP as b on  main.requestorid = b.requestorid
 left join tblB as blue on b.partyid = blue.partyid and YEAR(blue.AppliedDate) = @fYear

  group by  (case when description in ('Kecil', 'Tanah') then 'JK'
   else main.Description

端）

  ) t 
 order by (case when t.description =  'Amanah' then 1
                               when t.description = 'Mah' then 2
                               when t.description = 'JK' then 3
                               END) ASC

此输出如下：

需要遵循以下顺序：

我收到此错误：

  

在ORDER BY子句中无效，因为它不包含在   无论是聚合函数还是GROUP BY子句。

谢谢大家。

Answer 1

使用以下查询：

select * from (select @fYear as [Year],
(case when main.Description in ('Kecil', 'Tanah') then 'JK'
     else main.Description
end) as description,

--CardType,
sum(case when MONTH(blue.AppliedDate) = 1 then 1 else 0 end) as Jan_Collection,
sum(case when MONTH(blue.AppliedDate) = 2 then 1 else 0 end) as Feb_Collection,
...

from tblR as main
left join tblP as b on  main.requestorid = b.requestorid
left join tblB as blue on b.partyid = blue.partyid and YEAR(blue.AppliedDate) = @fYear

group by  (case when description in ('Kecil', 'Tanah') then 'JK'
       else main.Description
  end)

) t 
  order by (case when t.description =  'Amanah' then 1
                                   when t.description = 'Mah' then 2
                                   when t.description = 'JK' then 3
                                   END) ASC