Question

我尝试使用NOT contains（regex）

查询字符串重复字段

这是查询，其中nickname是字符串的数组（重复）：

 SELECT
    name
  FROM
    [mytable]
  WHERE
     (NOT  REGEXP_MATCH (nickname, '(query)'))

问题是当用户在昵称下至少有两个值时，如果我使用NOT查询它们将被返回

有关： NOT REGEXP_MATCH（昵称，＆＃39;（jonny）＆＃39;）

name     nickname 

john    [johhny,jonny]
jon     [jonny]

将返回约翰，它不应该。

Answer 1

使用NOT EXISTS或ARRAY子查询与standard SQL表达此类逻辑会更容易。例如，

#standardSQL
WITH Names AS (
  SELECT 'john' AS name, ['johnny', 'jonny'] AS nicknames UNION ALL
  SELECT 'jon' AS name, ['jonny'] AS nicknames
)
SELECT
  name
FROM Names
WHERE NOT EXISTS (
  SELECT 1 FROM UNNEST(nicknames) AS nickname
  WHERE nickname LIKE '%johnny%'
);

作为另一个例子，您可能只想包含与子字符串不匹配的昵称：

#standardSQL
WITH Names AS (
  SELECT 'john' AS name, ['johnny', 'jonny'] AS nicknames UNION ALL
  SELECT 'jon' AS name, ['jonny'] AS nicknames
)
SELECT *
FROM (
  SELECT
    name,
    ARRAY(SELECT nickname FROM UNNEST(nicknames) AS nickname
          WHERE nickname NOT LIKE '%johnny%') AS nicknames
  FROM Names
)
WHERE ARRAY_LENGTH(nicknames) > 0;

Answer 2

如果您仍然使用BigQuery Legacy SQL，则下面是相应的解决方案

#legacySQL
SELECT name FROM (
  SELECT
    name, SUM(nicknames LIKE '%johnny%') WITHIN RECORD AS matches
  FROM [mytable]
)
WHERE matches = 0

查询重复字段否定不包括

2 个答案: