Question

我是laravel的新人。请帮我解决这个问题，我打算这样做。

所以，就是这样。我想显示经过身份验证的用户未请求的游戏列表。因此，如果经过身份验证的用户请求了，例如：“dota 2”游戏。名称“dota 2”将不会显示在选项列表中，因为用户ID和游戏ID已记录在游戏表中。

这就是我所做的。

应用\游戏

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Game extends Model
{
    protected $fillable = [
        'user_id', 'games_id', 'username', 'password' 
    ];

    public function user()
    {
        return $this->belongsTo(User::class);
    }

    public function gamelist()
    {
        return $this->belongsTo(Gamelist::class);
    }

    public function scopeIncomplete($query)
    {
        return $query->where('completed', 0);
    }
}

应用\游戏列表

namespace App;

use Illuminate\Database\Eloquent\Model;

class Gamelist extends Model
{
    //
}

游戏桌迁移文件

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateGamesTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('games', function (Blueprint $table) {
            $table->engine = 'InnoDB';
            $table->increments('id');
            $table->integer('user_id')->unsigned();
            $table->integer('games_id')->unsigned();
            $table->string('username')->nullable();
            $table->string('password')->nullable();
            $table->boolean('completed')->default(false);
            $table->timestamps();
        });

        Schema::table('games', function($table) {
            $table->foreign('user_id')->references('id')->on('users');
            $table->foreign('games_id')->references('id')->on('gamelists');
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('games');
    }
}

Create_Gamelist_table迁移文件

<?php

use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateGamesListsTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('gamelists', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name');
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('gameslist');
    }
}

我想制作一个选择表格

<select>
    <option>{{-- This will display the name of the games that authenticated user haven't create or requested by using the table relation above--}}</option>
</select>

我被困住了，无法找到解决方案..请帮助:)

在这种情况下如何将多个表中的某些数据传递给视图？

0 个答案: