根据列值选择不同的行

时间:2017-03-08 23:15:00

标签: sql oracle

在一个表中我有四列'FirstName','LastName','Dob','Number' 唯一的'first Name'和'LastName'有多行,它们可以有相同或不同的'Number'和'Dob'值

FirstName  LastName   Dob         Number
Alice      Smith      02/03/77    0876543    (require)
Alice      Smith      Null        0876543    (Not require)
Alice      Smith      Null        Null       (Not require)
John       Adam       11/28/63    3265783    (require)
John       Adam       11/28/63    Null       (Not Require)
John       Adam       05/15/58    Null       (require)
Sally      Smith      Null        Null       (require)

我想要不同的行,但是如果'Number'或'Dob'与同一FirstName'和'LastName'的其他记录匹配,我只需要一条记录  我正在寻找上面示例中标记为“require”的行。我试过的组合没有得到我认为会有的结果。 感谢

1 个答案:

答案 0 :(得分:0)

我首先选择填充了所有四个字段的所有行:

SELECT DISTINCT FirstName, LastName, Dob, Number
FROM customers
WHERE Dob IS NOT NULL And Number IS NOT NULL

然后我会在选择中添加第一个选择中不存在的NOT NULL值的记录:

with RequiredSet as (
SELECT DISTINCT FirstName, LastName, Dob, Number
FROM customers
WHERE Dob IS NOT NULL And Number IS NOT NULL
), AdditionalSet as (
SELECT distinct c.FirstName, c.LastName, c.Dob, c.Number
FROM customers c
WHERE Dob IS NOT NULL And NOT EXISTS(SELECT 1 
   FROM RequiredSet r 
   WHERE r.FirstName = c.FirstName And r.LastName=c.LastName And r.Dob=c.Dob)
OR Number IS NOT NULL And NOT EXISTS(SELECT 1 
   FROM RequiredSet r 
   WHERE r.FirstName = c.FirstName And r.LastName=c.LastName And r.Number=c.Number)
)
SELECT FirstName, LastName, Dob, Number
FROM RequiredSet
UNION ALL 
SELECT FirstName, LastName, Dob, Number
FROM AdditionalSet