Question

我正在使用此C＃库连接到 Telegram API：TLSharp

此库的资源不足，我试图将邮件转发到频道。

我不确定如何获取频道peer ID（转发功能输入参数）

var store = new FileSessionStore();
            var client = new TelegramClient(Properties.Settings.Default.apiID, Properties.Settings.Default.apiHash, store, "session");
            await client.ConnectAsync();
            var dialogs = (TLDialogs)await client.GetUserDialogsAsync();
            var chat = dialogs.chats.lists
                .OfType<TLChannel>()
                .SingleOrDefault(a=>a.title=="test");
            await client.SendRequestAsync<TLAbsUpdates>(
                               new TLRequestForwardMessage()
                               {
                                   id = 2,
                                   peer = new TLInputPeerChannel() { channel_id = chat.id, access_hash = chat.access_hash.Value },
                                   random_id = Helpers.GenerateRandomLong()
                               });

我收到此错误消息：

{＆＃34; PEER_ID_INVALID＆＃34;}

请帮助我，该对等ID是什么以及如何使用TLSharp来访问和使用它来转发消息。感谢。

Answer 1

你可以用这个很有趣的好技巧来做到这一点：这段代码如下：

new TLInputPeerChannel { channel_id = chat.id, access_hash = cha.access_hash.Value }, offset,
                maxId, limit);

Answer 2

此代码可用于转发

**

/static

** ---------------------------------

Answer 3

这是我转发邮件的代码：

/* e.g you can use TLInputPeerUser, TLInputPeerChat, TLInputPeerChannel here as an SourcePeer */
// a Person
var sourcePeer = new TLInputPeerUser { UserId = <<<USER.ID>>>, AccessHash = <<<USER.AccessHash>>> };
    
// normal Group
//var sourcePeer = new TLInputPeerChat { ChatId = <<<USER.ID>>> };

// SuperGroup or Channel
//var sourcePeer = new TLInputPeerChannel { ChatId = <<<USER.ID>>> , AccessHash = <<<USER.AccessHash>>> };


/* e.g you can use TLInputPeerUser, TLInputPeerChat, TLInputPeerChannel here as an SourcePeer */
// a Person
//var targetPeer = new TLInputPeerUser { UserId = <<<USER.ID>>>, AccessHash = <<<USER.AccessHash>>> };

// normal Group
var targetPeer = new TLInputPeerChat { ChatId = <<<USER.ID>>> };

// SuperGroup or Channel
//var targetPeer = new TLInputPeerChannel { ChatId = <<<USER.ID>>> , AccessHash = <<<USER.AccessHash>>> };

// random Ids to prevent bombinggg
var randomIds = new TLVector<long>
{
    TLSharp.Core.Utils.Helpers.GenerateRandomLong()
};

// source messages
var sourceMessageIds = new TLVector<int>
{
    messageIdInSourceContactToForward   // this ID should be in the SourcePeer's Messages
};

var forwardRequest = new TLRequestForwardMessages()
{
    FromPeer = sourcePeer,
    Id = sourceMessageIds,
    ToPeer = targetPeer,
    RandomId = randomIds,
    //Silent = false
};

var result = await myTelegramClient.SendRequestAsync<TLUpdates>(forwardRequest);

我不能使用this method，而必须使用this one

使用TLSharp库转发消息（C＃）

3 个答案: