Question

我正在使用下面的代码在我的freeview框中输入带有我的频道名称的频道号，但由于编码没有列，所以它看起来像这样：

|    101  bbc one
|    102   bbc two
|    103  itv
|    104   channel 4

频道名称的开头由频道号码的宽度决定。我如何编辑我的代码，以便我的所有频道排列如下：

|    101  bbc one
|    102  bbc two
|    103  itv
|    104  channel 4

这是我的代码：

for number in customised["video"].keys():
customised["video"][number]["number"] = number

# swap channel numbers. Only swaps number. Channel swap is still done in bouquetwriter.py

       if 
providerConfig.isSwapChannels() and "swapchannels" in providers[section_identifier] and len(providers[section_identifier]["swapchannels"]) > 0 and "preferred_order" in providers[section_identifier]["swapchannels"][0]:

for swaprule in providers[section_identifier]["swapchannels"][0]["preferred_order"]:

       if 
swaprule[0] in services[section_identifier]["video"] and swaprule[1] in services[section_identifier]["video"] and services[section_identifier]["video"][swaprule[1]]["service_type"] >= 17:

customised["video"][swaprule[0]]["number"] = swaprule[1]
customised["video"][swaprule[1]]["number"] = swaprule[0]


for service in sorted(customised["video"].keys()):

       if 
service in range(1,2000):

       if 
"interactive_name" in customised["video"][service]:
customised["video"][service]["interactive_name"] = " " * 5 + str(customised["video"][service]["number"]) + " " * 4 + customised["video"][service]["interactive_name"]

     else:
customised["video"][service]["interactive_name"] = " " * 5 + str(customised["video"][service]["number"]) + " " * 4 + customised["video"][service]["service_name"]

Answer 1

目前还不清楚您的设置是什么，但假设第一个频道列表位于名为＆＃39; channels.txt＆＃39;的文件中，这样的内容可能有所帮助：

with open('channels.txt', 'r') as fh:
    channels = dict([ line.strip().split(None, 1) for line in fh.readlines() ])

channels现在看起来像这样：

{'102': 'bbc two', '103': 'itv', '101': 'bbc one', '104': ' channel 4'}

我无法告诉您如何构建customized，但这似乎是您想要的一部分。

Answer 2

现在你的问题与以前不同了同样，假设你想要的是一个名为channels.txt的文件，下面的代码会将它重写为你想要的格式：

with open('channels.txt', 'r') as fh:
    channels = '\n'.join([ '{} {:>5}  {}'.format(*line.strip().split(None, 2))
                           for line in fh.read().split('\n') ])

with open('channels.txt', 'w') as fh:
    fh.write(channels)

使用xml编码进行频道编号

2 个答案: