Question

所以我正致力于在Java上制作简单的刽子手游戏。计算机应从一组单词中选择一个随机单词：

public void setWords() {
    words[0] = "notions";
    words[1] = "measure";
    words[2] = "product";
    words[3] = "foliage";
    words[4] = "garbage";
    words[5] = "minutes";
    words[6] = "chowder";
    words[7] = "recital";
    words[8] = "concoct";
    words[9] = "brownie";       
}

我试图编写代码以在玩家玩游戏时生成随机单词：我将此作为首发：

public class Hangman {
private int numwords = 10;
private String[] words = new String[numwords];
private String gameWord;
private String dispWord = "-------";
private char[] dispArr = dispWord.toCharArray();



private static void main(String[] args) {
    System.out.println("Welcome to Hangman!:");

    Random rand= new Random();
    char c = rand.nextChar(setWords);
}

您能否帮助使用selectGameWord（）方法选择随机单词的语法？谢谢！

Answer 1

在你的主要内容中你可以选择这样的游戏单词。

String gameWord = words[rand.nextInt(words.length)];

如果你执行`.nextInt（10）＆＃39;，随机数的界限将是0 <= x <= 9。因为你的单词数组只有十个集合选择。

Answer 2

我相信你想从你的数组中得到一个随机的单词？您必须使用Random#nextInt()从数组中获取随机索引。

Random random = new Random();
int index = random.nextInt(words.length);
String randomWord = words[index];

Answer 3

https://stackoverflow.com/a/5887745/6934695

你可以用这个来获取随机数。

    import java.util.Random;

Random rand = new Random();    
int  n = rand.nextInt(words.length);
String word=selectGameWord(n)

和selectGameWord（int x）;

 sentence=words[x];
   return sentence;

编辑：

import java.util.Random;

public class Hangman{
    String words[]={"notions","measure","product","foliage"};



    public String selectGameWord(int x)
    {
        String sentence= words[x]; 
        return sentence; 
    }
    public static void main (String[] args){
        System.out.println("Welcome to Hangman!:"); 
        Random rand=new Random(); 
        Hangman myhangman= new Hangman();
        int n= rand.nextInt(myhangman.words.length);        
        String word= myhangman.selectGameWord(n); 
        System.out.println(word);
    }
}

Hangman游戏代码：

3 个答案: