Question

enter Access.Application oAccess = null;
        // Start a new instance of Access for Automation:
        oAccess = new Access.Application();
        // Open a database in exclusive mode:
        oAccess.OpenCurrentDatabase(@"C:\Users\me\documents\visual studio 2017\Projects\dbapp\dbapp\mydb.accdb", true);
        oAccess.Visible = true;`

以上是我从ji返回的json

    {
      "total_hits": 20277,
  "max_score": 10.676512,
  "hits": [
    {
      "_id": "513fceb375b8dbbc21000022",
      "fields": {
        "item_name": "Cheddar Cheese - 1 cup, diced",
        "brand_name": "USDA",
        "nf_calories": 531.96,
        "nf_total_fat": 43.74
      }
    },
    {
      "_id": "513fceb375b8dbbc2100001d",
      "fields": {
        "item_name": "Cheddar Cheese - 1 slice (1 oz)",
        "brand_name": "USDA",
        "nf_calories": 112.84,
        "nf_total_fat": 9.28
      }
    }
  ]
}

我正在返回一个JSON对象＆＃34;命中＆＃34;使用附加的代码但我想要做的是访问＆＃34;字段＆＃34;在这个对象的数组，但我一直无法做到这一点任何帮助都很高兴

提前致谢

Answer 1

以下是一些示例代码，用于说明如何使用org.json API：

    JSONObject raintopLevel = new JSONObject(rainbuilder.toString());
    JSONArray hits = raintoplevel.getJSONArray("hits");
    JSONObject obj = hits.getJSONObject(0); // first object in array
    String id = obj.getString("_id");
    JSONObject obj2 = obj.getJSONObject("fields");
    String itemName = obj2.getString("item_name");

Answer 2

＆＃34;命中＆＃34;是一个JSONArray，所以你必须使用JSONArray

JSONArray raintopLevel = rainbuilder.getJSONArray("hits");

然后你可以迭代数组

for (int i = 0; i < raintopLevel.length(); i++) {
    JSONObject json_hits = raintopLevel.getJSONObject(i);
    String id = json_id.getString("_id");
    JSONArray ja_fields= json_id.getJSONObject("fields");
    String item_name = ja_fields.getString("item_name");
}

Answer 3

“hits”不是JSONObject，而是JSONArray。所以你需要使用JSONArray。您可以使用以下代码。

JSONObject raintopLevel = new JSONObject(rainbuilder.toString());
JSONArray hits = raintoplevel.getJSONArray("hits");

JSONObject object11 = hits.getJSONObject(0); // for "hits"
String id = object11.getString("_id");

JSONObject object22 = object11.getJSONObject("fields"); // for "fields" that is inside "hits"
String item_name = object22.getString("item_name");
String brand_name = object22.getString("brand_name");

解析Json数据以从对象中提取数组

3 个答案: