Question

如果我的字符串包含最新的8位数的更新整数值：

 string Str = ("A1: [ " + int1 + " ] A2: [ " + int2  + " ]" +  
           "\r\nA3: [ " + int3 + " ] A4: [ " + int4  + " ]" +  
           "\r\nB1: [ " + int5 + " ] B2: [ " + int6  + " ]" + 
           "\r\nB3: [ " + int7 + " ] B4: [ " + int2  + " ]\r\n");

是：

  A1: [ 126.453 ] A2: [ 8.940 ]
  A3: [ 11.3 ] A4: [ 122.4 ]    
  B1: [ 6566.2 ] B2: [ 3444.76 ]    
  B3: [ 6.562 ] B4: [ 34.76 ]

我如何格式化迭代显示文本框输出并排作为列与部分之间的相应间距与计数整数大小：

  A1: [ 126.453 ] A2: [ 348656.2 ]    B1: [ 35.7 ] B2: [ 65.1 ] 
  A3: [ 8.90 ] A4: [ 34.76 ]          B3: [ 3.97770 ] B4: [ 87700.67 ]

我找到了几种方法，但不确定如何在这种情况下使用它，如何找出更新的数字并以这种方式将我的字符串分配给整数长度：

    int pd = 3;
    int mx1 = "Hello World!".Length;
    int mx2 = "1234.56732".Length;
    int mx3 = "Name".Length;

    string f0 = "{0,-" + (mx1 + pd) + "}";
    string f1 = "{1,-" + (mx2 + pd) + "}";
    string f2 = "{2,-" + (mx3 + pd) + "}";

    string f = f0 + f1 + f2;

    Console.WriteLine(f, "Hello World!", 1234.56732, "Month");
    Console.WriteLine(f, "How are you?", 78.44, "Day");
    Console.WriteLine(f, "Hi", 2311.654, "Year");

听听一些有用的建议会很好

Answer 1

您可以使用String.PadRight()方法来对齐值：

var nums = new List<double>() {
    126.453, 8.94, 11.3, 122.4, 6566.2, 3444.76, 6.562, 34.76
};

var maxLen = nums.Select(n => n.ToString().Length).Max();
var strVals = nums.Select(n => n.ToString().PadRight(maxLen)).ToList();

textBox1.Font = new Font(FontFamily.GenericMonospace, 10);
var pos = 0;
foreach (var strVal in strVals)
    //Debug.Write($"NUM{++pos}: [ {strVal} ]    {(pos % 2 == 0 ? "\r\n" : "")}");
    textBox1.Text += $"NUM{++pos}: [ {strVal} ]    {(pos % 2 == 0 ? "\r\n" : "")}";

<强>输出：

NUM1: [ 126,453 ]    NUM2: [ 8,94    ]    
NUM3: [ 11,3    ]    NUM4: [ 122,4   ]    
NUM5: [ 6566,2  ]    NUM6: [ 3444,76 ]    
NUM7: [ 6,562   ]    NUM8: [ 34,76   ]

使用更新的整数值格式化字符串，以文本框作为列显示

1 个答案: