具有前面序列号的Array的成员

Question

我想编写一个函数，该函数将数组作为参数，并返回一个字符串，其中数组中的项目具有前面的数字。例如。下面的line数组有三个成员Ava，Adam，John。我希望函数返回以下字符串：

The line is currently: 1. Ava, 2. Adam, 3. John

line = ['Ava', 'Adam', 'John']
function currentLine(line) {
  if (line.length === 0) {
    return "The line is currently empty.";
  }
  return "The line is currently: "
}

Answer 1

将此作为你的最后一句话：

var result = line.map(function (value, index) {
    return (index + 1) + '. ' + value;
}).join(', ');
return "The line is currently: " + result;

Answer 2

您可以通过以下方式完成此操作......

let line = ['Ava', 'Adam', 'John'];
function currentLine(line) {
  if (line.length !== 0) {
    let result = "The line is currently: ";
    line.forEach((e, i) => {
      result += (i + 1) + '. ' + e + ', ';
    });
    return result.slice(0,-2);
  } else return "The line is currently empty.";
}
console.log(currentLine(line));

Answer 3

var line = ['Ava', 'Adam', 'John']
function currentLine(line) {
    if (line.length === 0) {
        return "The line is currently empty.";
    }
    var newLine = line.map(function (item ,index){
    	return (index+1) + ". " + item;
    });
    return "The line is currently: " + newLine.join(", ");
}
console.log(currentLine(line));

Answer 4

纳兹-Al系，

此代码将允许您实现所需的结果。另外，您可以将其他数组传递给函数并实现相同的输出。

＆＃13;

＆＃13;

var line = ['Ava', 'Adam', 'John'];

function currentLine(array) {
 var output = "";
  if (array.length === 0) {
    return "The line is currently empty.";
  }
  else {
  	for(var i = 0; i < array.length; i++){
	  	output += (Number([i]) + 1) + ". " + array[i];
	  		if(i !== array.length - 1) {
	  			output = output + ", ";
	  		}
		}
	}
	return "The line is currently: " + output;
}

＆＃13;

＆＃13;

＆＃13;