Question

我有这个代码，我正在尝试解压缩。首先，我已经压缩了所有工作的代码，但是当我解压缩它时会出现一个ValueError。

    List.append(dic[int(bob)])
ValueError: invalid literal for int() with base 10: '1,2,3,4,5,6,7,8,9,'

这是代码......

def menu():
    print("..........................................................")
    para = input("Please enter a paragraph.")
    print()
    s = para.split()  # splits sentence
    another = [0]  # will gradually hold all of the numbers repeated or not
    index = []  # empty index
    word_dictionary = []  # names word_dictionary variable

    for count, i in enumerate(s):  # has a count and an index for enumerating the split sentence
        if s.count(i) < 2:  # if it is repeated
            another.append(max(another) + 1)  # adds the other count to another
        else:  # if is has not been repeated
            another.append(s.index(i) +1)  # adds the index (i) to another 
    new = " "  # this has been added because other wise the numbers would be 01234567891011121341513161718192320214
    another.remove(0)  # takes away the 0 so that it doesn't have a 0 at the start

    for word in s:  # for every word in the list
        if word not in word_dictionary:  # If it's not in word_dictionary
            word_dictionary.append(word)  # adds it to the dicitonary
        else:  # otherwise
            s.remove(word)  # it will remove the word

    fo = open("indx.txt","w+")  # opens file
    for index in another:  # for each i in another
        index= str(index)  # it will turn it into a string
        fo.write(index)  # adds the index to the file
        fo.write(new)  # adds a space
    fo.close()  # closes file

    fo=open("words.txt", "w+")  # names a file sentence
    for word in word_dictionary:
        fo.write(str(word ))  # adds sentence to the file
        fo.write(new)
    fo.close()  # closes file

menu()

index=open("indx.txt","r+").read()
dic=open("words.txt","r+").read()

index= index.split()
dic = dic.split()

Num=0
List=[]

while Num != len(index):
    bob=index[Num]
    List.append(dic[int(bob)])
    Num+=1

print (List)

问题出现在第50行。使用'List.append（dic [int（bob）]）'。有没有办法让错误信息停止弹出，并输出上面输入的句子代码？

发生了最新的错误消息： List.append（DIC [INT（BOB）]） IndexError：列表索引超出范围

当我运行代码时，我输入“这是一个句子。这是另一个句子，用逗号。”

Answer 1

问题是index= index.split()默认情况下是在空格上拆分，并且如异常所示，您的数字由,分隔。

没有看到index.txt我无法确定它是否会修复所有索引，但对于OP中的问题，您可以通过指定要拆分的内容来修复它，即逗号：

index= index.split(',')

关于第二个问题，List.append(dic[int(bob)]) IndexError: list index out of range有两个问题：

您的索引从1开始，而不是0，因此在重新构建数组时，您的索引是一个

这可以通过以下方式解决：

List.append(dic[int(bob) - 1])

此外，你做的工作比你需要的多得多。这样：

fo = open("indx.txt","w+")  # opens file
    for index in another:  # for each i in another
        index= str(index)  # it will turn it into a string
        fo.write(index)  # adds the index to the file
        fo.write(new)  # adds a space
    fo.close()  # closes file

相当于：

with open("indx.txt","w") as fo:
    for index in another:
        fo.write(str(index) + new)

和此：

Num=0
List=[]

while Num != len(index):
    bob=index[Num]
    List.append(dic[int(bob)])
    Num+=1

相当于

List = []
for item in index:
    List.append(dic[int(item)])

另外，请花点时间查看PEP-8并尝试遵循这些标准。您的代码很难阅读，因为它不遵循它们。我修改了你的评论格式，因此StackOverflow的解析器可以解析你的代码，但大多数只会增加混乱。

将两个压缩文件组合成一个段落

1 个答案: