Question

我的作业有困难...＆＃34;编写一个程序，询问用户两个数字：下部和上部。你的程序应该打印从下到上的所有Fibonacci数字以及Fibonacci系列中所有偶数的总和。＆＃34;我不知道如何获得两个输入之间的数字。现在它只是将数字从零到......？

这是我到目前为止所做的：

public static void main(String[] args) 
{
    Scanner scr = new Scanner(System.in);
    System.out.println ("Enter lower bound:");
    int lower = Integer.parseInt(scr.nextLine());
    System.out.println ("Enter upper bound:");
    int upper = Integer.parseInt(scr.nextLine());

    int fiboCounter = 1;
    int first = 0;
    int second = 1;
    int fibo = 0;
    int oddTotal = 1;
    System.out.println("The fibonacci numbers between ");
    while(fiboCounter < upper)
    {
        fibo= first + second;
        first = second;
        second = fibo;
        if(fibo % 2 == 0) 
            oddTotal = oddTotal + fibo;

        System.out.print(" "+ fibo+ " ");
        fiboCounter++;
    }
    System.out.println();
    System.out.println("Total of even Fibos: "+ oddTotal);
}

Answer 1

您只需检查计算出的数字是否足够大：

public static void main(String[] args) {
    Scanner scr = new Scanner(System.in);
    System.out.println ("Enter lower bound:");
    int lower = Integer.parseInt(scr.nextLine());
    System.out.println ("Enter upper bound:");
    int upper = Integer.parseInt(scr.nextLine());

    // This is how you can initialize multiple variables of the same type with the same value.
    int fiboCounter, second, oddTotal = 1;
    int first, fibo = 0;

    System.out.println("The fibonacci numbers between ");
    while( fiboCounter < upper ) {
        fibo= first + second;
        first= second;
        second=fibo;
        if(fibo%2==0) oddTotal=oddTotal+fibo;

        // Just check if its high enough
        if(fibo > lower ) {
            System.out.print(" "+ fibo + " ");
        }
        fiboCounter++;
    }

    System.out.println("\nTotal of even Fibos: "+ oddTotal);
    // The \n is just the same as System.out.println()

    // You probably want to close the scanner afterwards
    scanner.close();
}

我修改了一些代码并使其更具可读性。

两个输入之间的斐波纳契数

1 个答案: