Question

我想从PHP脚本中将信息插入到名为company的表中。我收到以下错误：

错误：INSERT INTO公司（id，name，description，hq，url，street， city_postcode，logo_path，employer_id，public_page，profile_picture） VALUES（1，Foo Bar，公司介绍，Phoenix， https://www.example.com，1234 S. Foo St，APT 123，Phoenix，85008， uploads / logos / company-default.png，1,0， uploads / companies / profile-picture-default.png）你有错误你的SQL语法;查看与MariaDB对应的手册服务器版本，用于在'Bar，Company附近使用正确的语法描述，凤凰城，https://www.example.com，1234 S. Foo St，APT' 在第2行

<?php

    // Create connection
    $conn = mysqli_connect($servername, $username, $password, $dbname);
    // Check connection
    if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
    }

    $id          = 1;
    $employer_id = 1;
    $public_page = 0;

    $name        = "Foo Bar";
    $description = "Company Description";
    $url         = "https://www.example.com";

    $address1 = "1234 S. Foo St";
    $address2 = "APT 123";
    $city     = "Phoenix";
    $state    = "Arizona";
    $postcode = "85008";

    $hq        = $city;
    $street    = $address1 . ", ". $address2;
    $city_post = $city . ", " . $postcode;

    $company_default_logo_path = "uploads/logos/company-default.png";
    $profile_picture_path      = "uploads/companies/profile-picture-default.png";

    $sql = "INSERT INTO company (id, name, description, hq, url, street, city_postcode, logo_path, employer_id, public_page, profile_picture)
      VALUES ($id, $name, $description, $hq, $url, $street, $city_post, $company_default_logo_path, $employer_id, $public_page, $profile_picture_path)";

    if (mysqli_query($conn, $sql)) {
      echo "New record created successfully";
    } else {
      echo "Error: " . $sql . "<br>" . mysqli_error($conn);
    }

    mysqli_close($conn);
?>

Mysql错误：INSERT INTO

0 个答案: