Question

我在React / Redux应用程序中使用redux-form，我正在试图找出如何在提交时发送动作。

我已经能够触发handleSubmit函数，并且执行了传递给它的submit函数，但是没有调用'submitFormValues'动作。

我尝试过使用mapDispatchToProps和connect（），但这也不起作用。

Redux-Form操作执行（START_SUBMIT，STOP_SUBMIT，SET_SUBMIT_SUCCEEDED），但我自己的动作创建者永远不会被执行。

以下是表格：

import React from "react";
import { Field, reduxForm } from "redux-form";
import {submitFormValues} from "../../../actions/BasicFormActions";


function submit(values) {
    //Can log the values to the console, but submitFormValues actionCreator does not appear to be dispatched.
    return new Promise(function(resolve) { resolve(submitFormValues(values))} )
}

const renderField = ({ input, label, type, meta: {touched, error} }) => (
    <div>
        <label>{label}</label>
        <div>
            <input {...input} placeholder={label} type={type}/>
            {touched && error && <span>{error}</span>}
        </div>
    </div>
)

const BasicForm = (props) => {
    const { error, handleSubmit, pristine, reset, submitting } = props;
    return (
        <form onSubmit={handleSubmit(submit)}>
            <Field name="firstName" type="text" component={renderField} label="First Name"/>
            <Field name="lastName" type="text" component={renderField} label="Last Name"/>
            {error && <strong>{error}</strong>}
            <div>
                <button type="submit" disabled={submitting}>Submit</button>
                <button type="button" disabled={pristine || submitting} onClick={reset}>Clear</button>
            </div>
        </form>
    )
}



export default reduxForm({
    form: "basicForm",
    submit
})(BasicForm)

这是动作创建者（使用Thunk）。我能够成功地发送这些动作，而不是从表格中发送。

 export const submitFormValues = (values) => (dispatch) =>
        getData("submitApproveForm", values).then(response => {
            dispatch(formSubmissionError(response))
        }).catch(error => {
            throw (error);
        });

const formSubmissionError = (response) =>
    ({
        type: types.FORM_SUBMISSION_ERROR,
        basicFormResponse: { ...response}
    });


export const getData = (apiName, args) =>
    fetch(settings.basePath + getUrl(apiName, args))
        .then(response =>
    response.json()
    ).catch(error => {
        return error;
    });

最后我的减速机：

import * as types from "../actions/ActionsTypes";
import initialState from "./initialState";

const basicFormReducer = (state = initialState.basicFormResponse, action) => {
    switch (action.type) {
        case types.FORM_SUBMISSION_ERROR:
            return {...state, "errors": action.basicFormResponse}; // returns a new state
        case types.FORM_SUBMISSION_SUCCESS:
            return {...state, "successes": action.basicFormResponse}; // returns a new state
        default:
            return state;
    }
};

export default basicFormReducer;

提前感谢您的帮助。

Answer 1

Redux Form不会在onSubmit回调中发送任何内容。这是因为我们不会假设您希望如何处理表单提交。

但是，您可以use the dispatch argument并......发送您的行动！

function submit(values, dispatch) {
    return dispatch(submitFormValues(values));
}

Redux-表格：无法在提交时发送行动

1 个答案: