我试图通过twilio的Record动词动作网址传递数据。当有两个或多个查询字符串参数时,它会失败,但是当只有一个查询字符串参数成功时。
成功:
var response = '<Response><Say>STUFF TO SAY</Say><Pause length="1"/><Record maxLength="3600" timeout="30" action="/service/training/call/recording?test1=test&test2=test"></Record></Response>';
失败:
var response = '<Response><Say>STUFF TO SAY</Say><Pause length="1"/><Record maxLength="3600" timeout="30" action="/service/training/call/recording?test1=test"></Record></Response>';
错误:
Error on line 1 of document : The reference to entity "test2" must end with the ';' delimiter.
有没有办法可以通过查询字符串传递数据,还是必须使用url参数? "/service/training/call/recording/test/test
答案 0 :(得分:2)
Twilio支持回到了我身边。这是他们的回应。
修复方法是更换&#39;&amp;&#39;在您的代码中使用它的有效XML替换 - &#39;&amp;&#39;。所以你的TwiML看起来像这样:
<?xml version="1.0" encoding="UTF-8"?>
<Response>
<Say>STUFF TO SAY</Say>
<Pause length="1"/>
<Record maxLength="3600" timeout="30" action="/service/training/call/recording?test1=test&test2=test">
</Record>
</Response>