Question

我想在html表格中的下面的示例图中最好地描述。我的表适用于来自MySQL数据库的数据，但所有数据都是按行打印的，这是正确的，但是我需要以下面的格式显示数据，并在Excel中显示相同的格式。这可以避免重复类似的数据。

我的SQL语句是：

$query = mysql_query("SELECT * FROM Reservations WHERE Date = '$DateToday' ORDER BY Airline ASC, Flight ASC, Name");

但我想要实现所需的显示php会比MySQL更有意义。

所以首先是while循环......

while ($row = mysql_fetch_array($query)) { $results = mysql_query("SELECT *      FROM Reservations WHERE Airline = '$Airline'");
$Count = mysql_num_rows($results);
if($Count > 1) // More then 1 passenger on same flight
{
  $iReservationID     = $row['ReservationID'];
  $iAirline           = strtoupper($row['Airline']);
  $iFlight            = strtoupper($row['Flight']);
  $iName              = strtoupper($row['Name']);
  $iName              = "<BR>".$iName;                        
} else {// NOT More then 1 passenger on same flight
    $ReservationID    = $row['ReservationID'];
    $Airline          = strtoupper($row['Airline']);
    $Flight           = strtoupper($row['Flight']);
    $Name             = strtoupper($row['Name']);                     
  } 
}
<table>
  <tr>
    <td>AIRLINE</td>";
    <td>FLIGHT#</td>";
    <td>PASSENGER</td>";
  </tr>
  <tr>
    <td>echo $Airline;</td>
    <td>echo $Flight;</td>
    <td>print "$Name<BR>$iName</td>
  </tr>
</table>

当只有一名乘客时，该表适用于每个条目的行，但在嵌套时它会复制乘客名称。

SELECT DISTINCT也没有做到这一点，SELECT FROM Reservations WHERE ReservationID <> $ReservationID - 我已经尝试了第二个WHILE循环来根据FLIGHT＃重新获取数据但仍然不正确。

建议非常感谢。

Answer 1

您可以尝试此代码

<?php
$query = mysql_query("SELECT *,GROUP_CONCAT(Name SEPARATOR '<BR>') AS PasName FROM Reservations WHERE Date = '$DateToday' GROUP BY Airline,Flight ORDER BY Airline ASC, Flight ASC, Name");
echo "<table>
<tr>
    <td>AIRLINE</td>
    <td>FLIGHT#</td>
    <td>PASSENGER</td>
</tr>";
while ($row = mysql_fetch_array($query)) {
    //$results = mysql_query("SELECT * FROM Reservations WHERE Airline = '$Airline'");

    $ReservationID = $row['ReservationID'];
    $Airline = strtoupper($row['Airline']);
    $Flight = strtoupper($row['Flight']);
    $Name = strtoupper($row['PasName']);

    //$Count = mysql_num_rows($results);
    /*if ($Count > 1) { // More then 1 passenger on same flight
        $iName = "";
        while ($inrow = mysql_fetch_array($results)) {
            $iName .= "<BR>".$inrow['Name'];
        }
    } else {// NOT More then 1 passenger on same flight
        // $ReservationID = $row['ReservationID'];
        // $Airline = strtoupper($row['Airline']);
        // $Flight = strtoupper($row['Flight']);
    }*/
    echo "<tr>
        <td>$Airline</td>
        <td>$Flight</td>
        <td>$Name</td>
    </tr>";
}
echo "</table>";
?>

但是，我建议您仅在查询中获取多个用户，即替换此查询

SELECT * FROM Reservations WHERE Airline = '$Airline'

与

SELECT GROUP_CONCAT(Name SEPARATOR '<BR>') FROM Reservations WHERE Airline = '$Airline' GROUP BY Airline,Flight

这样就不需要内部循环来连接用户名

Answer 2

试试这个

$sql = "SELECT * FROM Reservations WHERE Date = '$DateToday' ORDER BY Airline ASC, Flight ASC, Name";
$result = mysqli_query($conn, $sql);

if (mysqli_num_rows($result) > 0) {
    echo "<table>
              <tr>
                <td>AIRLINE</td>
                <td>FLIGHT#</td>
                <td>PASSENGER</td>
              </tr>
          ";
    while($row = mysqli_fetch_assoc($result)) {
        echo "<tr>
                <td>"+$row['ReservationID']+"</td>
                <td>"+strtoupper($row['Airline'])+"</td>
                <td>"+strtoupper($row['Flight'])+"</td>
                <td>"+MethodToFetchNameOfPassengersOfTheFlight(params)+"</td>
            </tr>";

    echo "</table>";
}

方法

string MethodToFetchNameOfPassengersOfTheFlight(params){
    //write a query to fetch the name of the passenger of the flight
    $CustomerNames = "";
    //in for each loop do this
    foreach($name in $names)
        $CustomerNames += $name + "<br>";
    return strtoupper($CustomerNames);
}

首先，我们展示航空公司的详细信息。然后我们找到相应航班的乘客并将它们串在一个断裂的字符串中，然后将它们分开。

在行内显示表行

2 个答案: