Question

create table dupt(cat varchar(10), num int)

insert dupt(cat,num) values ('A',1),('A',2),('A',3),
                            ('B',1),('B',2),
                            ('C',1),('C',2), ('C',3),
                            ('D',1),('D',2), ('D',4),
                            ('E',1),('E',2),
                            ('F',1),('F',2)

我需要创建一个查找重复数据的报告。从上面的示例数据中，报告需要显示cat A的数据由cat C复制（注意num值和记录的数量），cat B由cat E和F复制。显示该数据的最佳方式是什么？

示例输出

-------------
|cat | dupby|
-------------
| A  |  C   |
| B  | E, F |
-------------

Answer 1

更新：仅使用common table expression和stuff() with select ... for xml path ('') method of string concatenation切换到传统的集合匹配，仅用于最终结果：

;with cte as (
  select *
    , cnt = count(*) over (partition by cat)
  from t
)
, duplicates as (
  select 
        x.cat
      , dup_cat = x2.cat
  from cte as x 
    inner join cte as x2
       on x.cat < x2.cat
      and x.num = x2.num
      and x.cnt = x2.cnt 
  group by x.cat, x2.cat, x.cnt
  having count(*) = x.cnt
)
select 
    d.cat
  , dupby = stuff((
        select ', '+i.dup_cat
        from duplicates i
        where i.cat = d.cat
        for xml path (''), type).value('.','varchar(8000)')
     ,1,2,'')
from duplicates d
where not exists (
    select 1
    from duplicates i
    where d.cat = i.dup_cat
    )
group by d.cat

rextester演示：http://rextester.com/KHAG98718

返回：

+-----+-------+
| cat | dupby |
+-----+-------+
| A   | C     |
| B   | E, F  |
+-----+-------+

报告重复数据

1 个答案: