Question

我正在使用以下内容迭代节点组：

    <xsl:for-each select="NewDataSet/VehicleDetail/Options/Option">
    <xsl:choose>
        <xsl:when test="string-length(.) > 40">
            <div class="large">
                <xsl:value-of select="."/>
            </div>
        </xsl:when>
        <xsl:otherwise>
            <div class="small">
                <xsl:value-of select="."/>
            </div>
        </xsl:otherwise>
    </xsl:choose>
</xsl:for-each>

我希望能够做的是将大件物品（40个字符+）和小件物品（40个字符或更少）分组如下：

<div class="largeItems">
  <div class="large">Large Item</div>
  <div class="large">Large Item</div>
  <div class="large">Large Item</div>
  <div class="large">Large Item</div>
  <div class="large">Large Item</div>
</div>
<div class="smallItems">
  <div class="small">Small Item</div>
  <div class="small">Small Item</div>
  <div class="small">Small Item</div>
  <div class="small">Small Item</div>
  <div class="small">Small Item</div>
</div>

感谢。

Answer 1

尝试：

<div class="largeItems">
    <xsl:for-each select="NewDataSet/VehicleDetail/Options/Option[string-length() > 40]">
        <div class="large">
            <xsl:value-of select="."/>
        </div>
    </xsl:for-each>
</div>
<div class="smallItems">
    <xsl:for-each select="NewDataSet/VehicleDetail/Options/Option[string-length() &lt;= 40]">
        <div class="small">
            <xsl:value-of select="."/>
        </div>
    </xsl:for-each>
</div>

或者，如果您更喜欢重复代码：

<div class="largeItems">
    <xsl:apply-templates select="NewDataSet/VehicleDetail/Options/Option[string-length() > 40]">
        <xsl:with-param name="class" select="'large'"/>
    </xsl:apply-templates>
</div>
<div class="smallItems">    
    <xsl:apply-templates select="NewDataSet/VehicleDetail/Options/Option[string-length() > 40]">
        <xsl:with-param name="class" select="'small'"/>
    </xsl:apply-templates>
</div>

然后：

<xsl:template match="Option">
    <xsl:param name="class"/>
    <div class="{$class}">
        <xsl:value-of select="."/>
    </div>
</xsl:template>

未经测试，因为既未提供输入也未提供上下文。

使用XSLT 1.0有条件地对节点进行分组

1 个答案: