函数中的参数太少了

时间:2017-03-26 03:16:44

标签: c function parameters arguments

我正在写一个函数getIntLimited,只能在某个最大值和最小值之间的数字之外。目前没有指定的最大值或最小值,但代码应该基本上起作用。但是,我似乎得到一个错误,说我在函数中的参数太少,但我不确定为什么会这样。这是我的代码:

#include <stdio.h>
#include <stdlib.h>

//tools
void welcome(void);
void printTitle(void);
void printFooter(double gTotal);
void flushKeyboard(void);
void pause(void);
int getInt(void);
double getDouble(void);
int getIntLimited(int lowerLimit, int upperLimit);

//app interface
int yes(void);
void GroceryInventorySystem(void);
int menu(void);

int main(void){
    int iVal;
    double dVal;
    welcome();
    printTitle();
    double grandtotal = 1234.57;
    printFooter(grandtotal);
    flushKeyboard();
    pause();
    getInt();
    int lowLimit;
    int upLimit;
    getIntLimited(int lowLimit, int upLimit);

    return 0;
}


//code your functions here:

void welcome(void)
{
    printf("---=== Grocery Inventory System ===---");
    printf("\n");
    return;
}

void printTitle(void)
{
    printf("Row |SKU| Name          | Price |Taxed| Qty | Min |     Total    |Atn\n");
    printf("----+---+---------------+-------+-----+-----+-----+-------------|---");
    printf("\n");
    return;
}

void printFooter(double grandTotal)
{
    printf("--------------------------------------------------+-----------------");
    printf("\n");

    if (grandTotal > 0) {
    printf("                                     Grand Total: |     %12.2lf",  grandTotal);
            }
    printf("\n");
                                        return;
}


void flushKeyboard(void)
{
    int read;

    while (( read = getchar()) != '\n')
    return;
}

void pause(void)
{
    printf("Press <ENTER> to continue...\n");
    flushKeyboard();
    return;
}

int getInt(void)
{
    int Value;
    char NL = 'x';

    while (NL != '\n') {
            scanf("%d%c", &Value, &NL);

if (NL != '\n') {
            flushKeyboard();
            printf("Invalid integer, please try again: \n");
        }
    }
    return Value;
}

int getIntLimited(int lowerLimit, int upperLimit)
{
    int limit;
    do {
            limit = getInt();

            if(lowerLimit > limit || limit > upperLimit) {
                    printf("Invalid value, %d < %d < %d: ", lowerLimit, limit,   upperLimit);
            }
    }

            while(lowerLimit < limit && limit < upperLimit);
    return limit;

}                             

2 个答案:

答案 0 :(得分:6)

var locations = [ ['FULL',3.720185, 103.124075,1], ['EMPTY',3.719693, 103.123896,0], ['FULL',3.720916, 103.12492,1], ['EMPTY',3.721032, 103.124532,0], ['FULL',3.722299, 103.124587,1], ['FULL',3.723189, 103.124706,1], ['FULL',3.725067, 103.124593,1] ]; var full = 0; var empty = 0; for(var i = 0; i < locations.length; i++){ for(var j = 0; j < locations[i].length; j++){ if(locations[i][j] == 'FULL') full++; if(locations[i][j] == 'EMPTY') empty++; } } console.log("full " + full + " empty " + empty );函数中,这不是函数调用:

main

删除getIntLimited(int lowLimit, int upLimit); 个关键字:

int

另请注意,getIntLimited(lowLimit, upLimit); lowLimit在传递给upLimit时未初始化。读取未初始化的值会调用未定义的行为。

答案 1 :(得分:1)

getIntLimited(int lowLimit,int upLimit);而不是这个使用getIntLimited(lowLimit,upLimit);在函数调用期间不需要数据类型

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