Question

我有这样的数据

dt                 | price
---------------------------
2016-02-02 12:33:33  3.3
2016-03-02 12:33:33  3.3
2016-02-02 12:03:33  3.3
2016-02-02 12:50:33  3.3
2016-02-02 13:33:33  3.3

我需要按小时分组的总和价格，但我需要包括年，月和日部分

理想的结果：

2016-02-02 12:00:00  9.9
2016-02-02 13:00:00  3.3
2016-03-02 12:00:00  3.3

我有查询，它给出了这个结果。问题是，可能有更有效的方法来做到这一点吗？

我当前的查询：

SELECT TO_TIMESTAMP(d, 'YYYY-MM-DD HH24:MI:SS') AS hours, price FROM (
    SELECT substr(dt, 1, 13) AS d, sum(price) as price FROM table
    GROUP BY substr(dt, 1, 13)
) 
ORDER BY hours

Answer 1

试试这个

select
TRUNC(dt,'HH24'),
sum(price)
from table
group by TRUNC(dt,'HH24')
order by 2 desc;

Answer 2

使用to_char：

select to_char(dt, 'YYYY-MM-DD HH24')||':00:00' as HourBlock, sum(price) as TotalPrice
from MyTable
group by to_char(dt, 'YYYY-MM-DD HH24')||':00:00'

按小时分组价格

2 个答案: