我的js在另一个浏览器中工作,但不在chrome中

时间:2017-03-28 15:10:13

标签: javascript jquery

当我点击按钮时,ajax必须加载更多内容并将用户置于新的加载内容之上。功能在mozilla和IE中完美运行但不在Chrome中我不知道问题出在哪里。提前谢谢。

if ($showMoreOffersButton) { ?>
        <div class="text-center box" id="show-more-tourism-offers-btn-holder">
            <a class="site-button blue" onclick="showMoreTourismOffers(<?php echo $offset; ?>)"
               onclick="ga('send', 'event', '<?= isset($parent_component) ? $parent_component : 'Unknown' ?>', 'Show More Offers' );">
                <span class="glyphicon glyphicon-refresh spinning" id="travel-arrow-spinner"
                      style="display: none"></span>
                ОЩЕ ОФЕРТИ
            </a>
        </div>
    <? }



function showMoreTourismOffers(begin_offset) {
if (!btn_lock) {
    //check if user already visited this page and saw more than 16 boxes
    if (offset < begin_offset) {
        offset = begin_offset;
    }
    var mobileFlag;
    if(isMobile == 1){
        mobileFlag = true;
    }else{
        mobileFlag = false;
    }
    $.ajax({
        url: base_url + 'pochivki/show_more_offers/',
        type: 'POST',
        data: {
            filter: ajaxDealFilter(true, mobileFlag),
            country_index: countryIndex,
            region_index: regionIndex,
            city_index: cityIndex,
            offset: offset,
            current_url: window.location.href
        },
        success: function (data) {
            $('#tourism-deals-holder').append(data.deals);
            if (data.hideButton) {
                $('#show-more-tourism-offers-btn-holder').remove();
            }
             offset += 48;
            $('#travel-arrow-spinner').hide();
        },
        error: function () {
        },
        beforeSend: function () {
            btn_lock = !btn_lock; // becomes true
            $('#travel-arrow-spinner').show();
        },
        complete: function () {
            btn_lock = !btn_lock; // becomes false again
            $('.images-rotation').imagesRotation()
        },
        dataType: "json"
    });
}   }

1 个答案:

答案 0 :(得分:-1)

解决这个问题我希望任何有同样问题的人帮助

if( sensorVal <= treshold ) {
  Serial.println("Watering");
  waterOn();
} else {
  Serial.println("NOT watering");
  waterOff();
}

}

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