我一直在为字母（a-z）制作java猜谜游戏！然而，我通过使用数字1-26完美地创建了游戏，但我无法弄清楚如何将每个整数转换为字母，即a = 1，b = 2，.... z = 26！
我希望用户尝试猜测字母而不是数字，但我无法锻炼如何做到这一点！
（我知道如何生成随机字符，但我无法实现并将其正确链接到游戏中的每个整数）
Random r = new Random();
char targetLetter = (char)(r.nextInt(26) + 'a');
任何帮助将不胜感激！如果需要，我可以显示我的代码
public class Stack {
public static void main(String[] args) {
Random rand = new Random(); //This is were the computer selects the Target
int guess;
int numGuesses = 0;
int Target;
String userName;
String playagain;
boolean play = true;
int session = 0;
int sessions = 0;
int bestScore = 0;
Scanner consoleIn = new Scanner(System.in);
Scanner name = new Scanner(System.in);
System.out.println("Hello! Please enter your name:\n"); //This is were the user enters his/her name
userName = name.nextLine();
System.out.println("Hello " + userName + " :) Welcome to the game!\n");
while (play = true) {
session++;
Target = rand.nextInt(26) + 1;
System.out.println("Guess a number between 1 and 26? You will have 5 attempts to guess the correct number"); //This is where the computer asks the user to guess the number and how many guesses they will have
do {
guess = consoleIn.nextInt();
numGuesses++;
if (guess > 26)
System.out.println("Error! Above MAXIMUM range");
else if (guess <= 0)
System.out.println("Error! Below MINIMUM range");
else if (guess > Target)
System.out.println("Sorry! Your guess was too high! :)"); //This is to help the player get to the answer
else if (guess < Target)
System.out.println("Sorry! Your guess was too low! :)"); //This is to help the player get to the answer
} while (guess != Target && numGuesses < 5);
if (guess == Target) {
System.out.println("Congratulations " + userName + ", it took you " + numGuesses + " attempts to guess correctly!"); //This tells the player that they got the correct answer and how many attempts it took
sessions++;
} else {
System.out.println("Sorry " + userName + ", You've used up all of your guesses! The correct answer was " + Target + "!"); //This tells the player that they failed to find the number and then tells them what the correct answer
}
{
Scanner answer = new Scanner(System.in);
System.out.println("Would you like another GO " + userName + "? [Y/N]");//This asks the player if they would like to play again
playagain = answer.nextLine();
if (playagain.equalsIgnoreCase("Y")) {//This is what happens if the player opts to play again
play = true;
numGuesses = 0;
} else if (playagain.equalsIgnoreCase("N")) {//This is what happens if the player opts to exit the game
play = false;
System.out.println("Thanks for playing " + userName + "! :) Please come back soon!");
System.out.println("You had " + session + " Goes");
System.out.println("The number of times you guessed correctly: " + sessions + "");
break;
}
}
}
}
}
答案 0 :(得分：0)
使用字符数组
char[] chars = ['A','B','C'...];
并使用随机数映射到每个字符
char targetLetter = chars[r.nextInt(26)];
答案 1 :(得分：0)
public static void main(String args[])
{
Scanner scan = new Scanner(System.in);
System.out.println("Guess the Letter");
String myLetter=scan.nextLine();
//get the letter of myLetter variable then convert to Uppercase
char enteredLetter=Character.toUpperCase(myLetter.charAt(0));
//26 only because the characters array starts with index 0
char[] characters ={'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
//I had created a parrallel array symbolizing int value of each letter
int[] range={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26};
//this variable convert user input to one of the array element of range
int userInputToInt=0;
//this variable is for knowing what int[] range array element must the value of userInputToInt fall
int userInputControlLoop=0;
char randomLetter=characters[(int)(Math.random()*26)];
// get the random input of computer convert it to int
int computerInputToInt=0;
//this loop is for getting the int value of randomLetter input by the computer
for(int i=0;i<characters.length;++i)
{
if(randomLetter==characters[i])
{
computerInputToInt=range[i];
}
}
//this loop is for getting the int value of user inputted letter
for(char i:characters)
{
if(enteredLetter==i)
{
userInputToInt=range[userInputControlLoop];
}
++userInputControlLoop;
}
//test the entered letter of user
if(enteredLetter==randomLetter)
{
System.out.println("Correct Guess");
System.out.println("The letter is:"+randomLetter);
}
//test the entered letter of user if greater than computer input
else if(userInputToInt>computerInputToInt)
{
System.out.println("Incorrect Guess");
System.out.println("The letter is too high");
System.out.println("The letter is:"+randomLetter);
}
//test the entered letter of user if lesser than computer input
else if(userInputToInt<computerInputToInt)
{
System.out.println("Incorrect Guess");
System.out.println("The letter is too low");
System.out.println("The letter is:"+randomLetter);
}
}
答案 2 :(得分：0)
使用与随机字符相同的方法。假设您将猜测的字符作为名为“guess”的int变量，并且它具有值1-26对应的A-Z：
Random r = new Random();
char targetLetter = (char)(r.nextInt(26) + 'a');
...
int guess = ...
char guessChar = (char)guess + 'a';
if (guessChar == targetLetter) {
System.out.println("Correct!");
} else {
System.out.println("Guess again!")
}
答案 3 :(得分：0)
您可以使用此方法实现它：
1-使用您想要的字符创建字符串alphabet。
2-将字母大小声明为n变量，它将控制随机生成器范围。
3- alphabet.charAt(random.nextInt(n))是字母表中的随机字符。
程序代码将是：
String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int n = alphabet.length();
Random r = new Random();
System.out.println(alphabet.charAt(r.nextInt(n)));
希望有助于解决您的问题。