Question

你好:)我其实想问问题所以我的目标是“如果我点击按钮1，按钮2也会被点击”

“可以吗？点击一个按钮，然后点击另一个按钮？”

这是我的代码：

Button btn1 = sender as Button;

if (btn1 == button1){
    button2.PerformClick();
}

它实际上不起作用似乎有什么不对

Answer 1

我建议提取方法。

在：

private void button1_Click(object sender, EventArgs e)
{
  Routine 1 code ...
  Routine 2 code ... // <- do not copy yourself; copy + paste is evil!
}

private void button2_Click(object sender, EventArgs e)
{
  Routine 2 code ...
}

后：

//TODO: think over the right name
private void Routine1() 
{ 
  Routine 1 code ...
}

//TODO: think over the right name 
private void Routine2() 
{ 
  Routine 2 code ...
}

...

private void button1_Click(object sender, EventArgs e)
{
  Routine1();
  Routine2();
}

private void button2_Click(object sender, EventArgs e)
{
  Routine2();
}

Answer 2

这很简单。

   private void button1_Click(object sender, EventArgs e)
    {
        if ((sender as Button) == button1)
        {
            button2_Click(sender, e);
        }
    }

    private void button2_Click(object sender, EventArgs e)
    {

    }

Answer 3

除非你有这样做的奇怪理由，否则不要！

你应该喜欢这样的东西：

void button1_Click(object sender, EventArgs e)
{
    DoWork1();
    DoWork2();
}

void button2_Click(object sender, EventArgs e)
{
    DoWork2();
}

一次点击2按钮

3 个答案: