Question

我使用APIView来获取和发布项目我想使用Django Rest Framework为我的API实现分页，但它不起作用。

我想在每页显示10个项目，但是当我api/v1/items?page=1时，我会收到所有项目，如果我只是api/v1/items，我会得到一个空列表。

这就是我所做的：

from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger

class ItemsAPIView(APIView):
    permission_classes = (permissions.IsAuthenticated,)

    def get(self, request, format=None):
        """
        Return a list of all items of this user.
        """
        reply = {}
        page = request.GET.get('page')
        print ('page is', page)
        try:
            products = BaseItem.objects.owned_items().filter(owner=request.user)
            reply['data'] = OwnedItemSerializer(products, many=True).data

            items = BaseItem.objects.filter(owner=request.user)
            paginator = Paginator(items, 1)
            items_with_pagination = paginator.page(page)
            if page is not None:
                reply['data'].extend(ItemSerializer(items_with_pagination, many=True).data)
            reply['data'].extend(ItemSerializer(items, many=True).data)

Answer 1

django rest框架文档中所述的非通用视图和视图集do not have pagination by default：

只有在您使用通用视图或视图集时，才会自动执行分页。如果您使用常规APIView，则需要自行调用分页API以确保返回分页响应。有关示例，请参阅mixins.ListModelMixin和generics.GenericAPIView类的源代码。

我已经编写了一个full example on enabling pagination on non generic views代码，其中包含如何实现此目的的代码：

class ItemsAPIView(APIView):
    permission_classes = (permissions.IsAuthenticated,)
    pagination_class = api_settings.DEFAULT_PAGINATION_CLASS
    serializer_class = MyNewUnifiedSerializerClass

    def get(self, request):
        user_items =  BaseItem.objects.filter(
                          owner=request.user
                      ).distinct()
        page = self.paginate_queryset(user_items)

        if page is not None:
            serializer = self.serializer_class(page, many=True)
            return self.get_paginated_response(serializer.data)

        serializer = self.get_serializer(user_items, many=True)
        return Response(serializer.data)

    # Now add the pagination handlers taken from 
    #  django-rest-framework/rest_framework/generics.py

    @property
    def paginator(self):
        """
        The paginator instance associated with the view, or `None`.
        """
        if not hasattr(self, '_paginator'):
            if self.pagination_class is None:
                self._paginator = None
            else:
                self._paginator = self.pagination_class()
            return self._paginator

     def paginate_queryset(self, queryset):
         """
         Return a single page of results, 
         or `None` if pagination is disabled.
         """
         if self.paginator is None:
             return None
         return self.paginator.paginate_queryset(
                    queryset, 
                    self.request, 
                    view=self
                )

     def get_paginated_response(self, data):
         """
         Return a paginated style `Response` object 
         for the given output data.
         """
         assert self.paginator is not None
         return self.paginator.get_paginated_response(data)

有关详细信息，请查看example link provided。

Answer 2

paginator =无为我工作

> class NotesViewSet(viewsets.ModelViewSet):    
>     queryset = Notes.objects.all()
>     serializer_class = NotesWriteSerializer
>     paginator = None

Answer 3

你可以让你的生活更轻松，只需使用ListView。通过重写render_to_response，您可以使其输出json而不是HTML。它为你做了所有的分页。

from django.core import serializers
from django.views.generic import ListView

class MyListView(JSONResponseMixin, ListView):
    model = models.BaseItem    
    paginate_by = 10  

    def render_to_response(self, context):
        return JsonResponse(
            serializers.serialize("json", context),
            **response_kwargs
        )

Answer 4

延长GenericAPIView而不是APIView 并在pagination_class

中定义GenericAPIView

分页在DRF APIView中不起作用

4 个答案: