将方法的返回值传递给另一个方法作为参数,在单独的方法

时间:2017-04-03 19:31:27

标签: c++ methods

这比我保证的声音更简单。我查过了其他帖子,但我还没有成功找到任何帖子。

我有一个方法AList::GenerateRandom()

void AList::GenerateRandom(){
    int randomAmount;
    int randomLimitHigh;
    srand(int(time(0)));

    cout << "\nResetting the current list using randomly generated elements.\n\n";
    cout << "Enter the desired number of elements (0 to 50): " ;
    randomAmount = ReadRandomAmount();
    randomLimitLow = ReadRandomLimitLow();
    randomLimitHigh = ReadRandomLimitHigh(randomLimitLow);

    cout << "\n\nFinished resetting, " << randomAmount << "elements between" <<  randomLimitLow << " and " << randomLimitHigh << "randomly generated.\n\n";
  }

在我决定最好包含randomLimitLow的值之前,一切正常。

现在我收到了这个含糊不清的错误:

Undefined symbols for architecture x86_64:
  "AList::ReadRandomAmount()", referenced from:
      AList::GenerateRandom() in AList-2fa708.o
  "AList::ReadRandomLimitLow()", referenced from:
      AList::GenerateRandom() in AList-2fa708.o
ld: symbol(s) not found for architecture x86_64

以下是其他方法的内容

int ReadRandomAmount(){
        int randomAmount;        // used to collect the user's input
        cin >> boolalpha >> randomAmount;

        while (! cin.good() || randomAmount < 0 || randomAmount > 50) {

                cin.clear();

                cin.ignore(80, '\n');

               if(!cin.good()){
                  cout << "Invalid data type, should be an element ("
                        << ELEMENT_NAME
                        << "), try again: ";
                  } else
                  cout << "Invalid range type, should be within 0 and 50, try again: ";

                cin >> boolalpha >> randomAmount;
                }

        return randomAmount;
    }

  int ReadRandomLimitLow(){
        int randomLimitLow;        // used to collect the user's input

        cin >> boolalpha >> randomLimitLow;

        while (! cin.good() || randomLimitLow < 0 || randomLimitLow > 2147483646) {

                cin.clear();

                cin.ignore(80, '\n');

               if(!cin.good()){
                  cout << "Invalid data type, should be an element ("
                        << ELEMENT_NAME
                        << "), try again: ";
                  } else
                  cout << "Invalid range type, should be within 0 and 2147483646, try again: ";

                cin >> boolalpha >> randomLimitLow;
                }

        return randomLimitLow;
    }

  int ReadRandomLimitHigh(int randomLimitLow){
        int randomLimitHigh;        // used to collect the user's input

        cin >> boolalpha >> randomLimitHigh;


        while (! cin.good() || randomLimitHigh < randomLimitLow || randomLimitHigh > 2147483647) {


                cin.clear();


                cin.ignore(80, '\n');


               if(!cin.good()){
                  cout << "Invalid data type, should be an element ("
                        << ELEMENT_NAME
                        << "), try again: ";
                  } else
                  cout << "Invalid range type, should be within " << randomLimitLow << " and 2147483647, try again: ";

                cin >> boolalpha >> randomLimitHigh;
                }

        return randomLimitHigh;
    }

我如何确保ReadRandomLimitHigh()只会获取大于ReadRandomLimitLow()

值的值

0 个答案:

没有答案
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