Question

给出以下数组： -

$array = Array(
    [key1] = Array
    (
      [0] => 5
      [1] => Array(1,2,3)
    )
    [key2] = Array
    (
      [0] => 15
      [1] => Array(11,32,3,5)
    )
    ...
)

如何过滤$array[key][1]等于给定Array(1,2,3)的所有元素？

Answer 1

您可以这样使用数组过滤器：

$array = Array(
        'key1' => Array
        (5,Array(1,2,3)),
        'key2' => Array
        (15,Array(11,32,3,5))
);

function changeArray($array, $parameter) {
    return array_filter($array, function($v) use ($parameter) {
        return $v[1] == $parameter;
    });
}

var_dump(changeArray($array, Array(1,2,3)));

?>

Answer 2

PHP的array_filter()函数很容易阅读：

<?php
$input = [
    'key1' => [
        0 => 5,
        1 => [1,2,3]
    ],
    'key2' => [
        0 => 15,
        1 => [11,32,3,5]
    ],
    'key3' => [
        0 => 15,
        1 => [1,2,3]
    ],
    'key4' => [
        0 => 151,
        1 => [11,32,3,5]
    ],
    'key5' => [
        0 => 15,
        1 => [1,2,3,4,5]
    ]
];
$pattern = [1,2,3];
$output = array_filter($input, function($subject) use ($pattern) {
    return $pattern === $subject[1];
});
print_r(array_keys($output));

上述代码的输出显然是：

Array
(
    [0] => key1
    [1] => key3
)

PHP - 过滤多维数组

2 个答案: