Question

我正在使用带有php的ajax来排序和显示我的数据库。但是我不能在asc和desc之间切换。它只适用于ASC，虽然我不知道为什么。无论我按下按钮多少次，$ isAsc都保持在1。（我使用的是PHP 7.1） // AJAX

$('#sort_by_name').click(function(e){
    e.preventDefault();
    $.ajax({
        url: "data.php?order=<?php echo isset($_GET['order'])?!$_GET['order']:1; ?>",
        type: 'POST',
        asynch: false,
        data: {
            "sort_by_name":1
        },
        success: function(d){                
            $('#movie_container').html(d);
        }
    });
});

// PHP

if (isset($_POST['sort_by_name'])) {
$isAsc = isset($_GET['order']) ? (bool) $_GET['order'] : 1;
if ($isAsc) {
    $sql = "SELECT id, movie_name, movie_year, movie_rating, movie_description, movie_imdb, movie_image, movie_my_rating FROM movies ORDER BY movie_name ASC";
    $result = $con->query($sql);
    if ($result->num_rows > 0) {
        while ($row = $result->fetch_assoc()) {
            $rowcount = mysqli_num_rows($result);
            include 'show_movie_and_ribbon.php';
        }
    }
} else {
    $sql = "SELECT id, movie_name, movie_year, movie_rating, movie_description, movie_imdb, movie_image, movie_my_rating FROM movies ORDER BY movie_name DESC";
    $result = $con->query($sql);
    if ($result->num_rows > 0) {
        while ($row = $result->fetch_assoc()) {
            $rowcount = mysqli_num_rows($result);
            include 'show_movie_and_ribbon.php';
        }
    }
}

}

Answer 1

使用JS获取url参数：

将订单参数插入数据。

检查此代码：

的Javascript

function getUrlParameter(sParam) {
            var sPageURL = decodeURIComponent(window.location.search.substring(1)),
                sURLVariables = sPageURL.split('&'),
                sParameterName,
                i;


        for (i = 0; i < sURLVariables.length; i++) {
            sParameterName = sURLVariables[i].split('=');

            if (sParameterName[0] === sParam) {
                return sParameterName[1] === undefined ? true : sParameterName[1];
            }
        }
    }


    $('#sort_by_name').click(function(e){
        e.preventDefault();
        $.ajax({
            url: "data.php",
            type: 'POST',
            asynch: false,
            data: {
                "sort_by_name":1,
                 "order":getUrlParameter('order')?:1
            },
            success: function(d){                
                $('#movie_container').html(d);
            }
        });
    });

PHP

if (isset($_POST['sort_by_name'])) {
$isAsc = isset($_POST['order']) ? $_POST['order'] : 1;
if ($isAsc) {
    $sql = "SELECT id, movie_name, movie_year, movie_rating, movie_description, movie_imdb, movie_image, movie_my_rating FROM movies ORDER BY movie_name ASC";
    $result = $con->query($sql);
    if ($result->num_rows > 0) {
        while ($row = $result->fetch_assoc()) {
            $rowcount = mysqli_num_rows($result);
            include 'show_movie_and_ribbon.php';
        }
    }
} else {
    $sql = "SELECT id, movie_name, movie_year, movie_rating, movie_description, movie_imdb, movie_image, movie_my_rating FROM movies ORDER BY movie_name DESC";
    $result = $con->query($sql);
    if ($result->num_rows > 0) {
        while ($row = $result->fetch_assoc()) {
            $rowcount = mysqli_num_rows($result);
            include 'show_movie_and_ribbon.php';
        }
    }
}

问题上升和下降

1 个答案:

的Javascript

PHP