Question

All I want to do is convert a single Character to uppercase without the overhead of converting to a String and then calling .uppercased(). Is there any built-in way to do this, or a way for me to call the toupper() function from C without any bridging? I really don't think I should have to go out of my way for something so simple.

Answer 1

To call the C toupper() you need to get the Unicode code point of the Character. But Character has no method for getting its code point (a Character may consist of multiple code points), so you have to convert the Character into a String to obtain any of its code points.

So you really have to convert to String to get anywhere. Unless you store the character as a UnicodeScalar instead of a Character. In this case you can do this:

assert(unicodeScalar.isASCII) // toupper argument must be "representable as an unsigned char"
let uppercase = UnicodeScalar(toupper(CInt(unicodeScalar.value)))

But this isn't really more readable than simply using String:

let uppercase = Character(String(character).uppercased())

Answer 2

只需将其添加到您的程序中

extension Character {
    
    //converts a character to uppercase
    func convertToUpperCase() -> Character {
        if(self.isUppercase){
            return self
        }
        return Character(self.uppercased())
    }
}

How can I convert a single Character type to uppercase?

2 个答案: