Python check if list only contains either empty elements or whitespace

Question

I would like to check if a list only contains either empty elements or whitespace, something like:

l = ['','   ','\n']
if all(whitespace or empty for element in l):
    return True

Anyone know how to do this?

Answer 1

Well your whitespace is simply str.isspace(..) so:

if all('' == s or s.isspace() for s in l):
    return True

Answer 2

The easiest way is probably to use str.strip(), which will return the empty string if the source string contains only whitespace. The empty string is falsey.

if not any(s.strip() for s in l): return True

Answer 3

Try this:

if not any(s.strip() for s in l):
    return True

Answer 4

Slightly different answer using all instead of any:

if  all([not x.strip() for x in l]):
    return True

Answer 5

另一种获得所需结果的方法，但使用str.split（）：

if all(not x.split() for x in l):
   return True