给定两个订阅者,同步处理来自RabbitMQ队列的Message对象,一次一个3s ,
当发布商发送4封邮件时:
消息{文字:1}
消息{文字:2}
消息{文字:3}
消息{文字:4}
是否可以通过这种方式划分工作:
Subscriber1 - 1 - 00:00:00
Subscriber2 - 2 - 00:00:00
Subscriber1 - 3 - 00:00:03
Subscriber2 - 4 - 00:00:03
以便订阅者立即开始前两条消息,然后,当它们完成时,使用下一条消息?订单对我来说并不重要。我想使用EasyNetQ,因为它的api很好,但默认的.NET / C#RabbitMQ客户端也没问题。
此代码无法正常工作:
var Bus = RabbitHutch.CreateBus("host=localhost");
Bus.Subscribe<Message>("subscriptionId", x =>
{
Console.WriteLine("Subscriber1 - " + x.Text + " - " + DateTime.Now.ToString("HH:mm:ss"));
Thread.Sleep(3000);
});
Bus.Subscribe<Message>("subscriptionId", x =>
{
Console.WriteLine("Subscriber2 - " + x.Text + " - " + DateTime.Now.ToString("HH:mm:ss"));
Thread.Sleep(3000);
});
Bus.Publish(new Message("1"));
Bus.Publish(new Message("2"));
Bus.Publish(new Message("3"));
Bus.Publish(new Message("4"));
任何?
答案 0 :(得分:1)
我明白了。 应该是这样的:
Bus = RabbitHutch.CreateBus("host=localhost;prefetchcount=1");
Bus.SubscribeAsync<Message>("subscriptionId", async x =>
{
Console.WriteLine("Subscriber1 - " + x.Text + " - " + DateTime.Now.ToString("HH:mm:ss"));
await Task.Delay(3000);
});
Bus.SubscribeAsync<Message>("subscriptionId", async x =>
{
Console.WriteLine("Subscriber2 - " + x.Text + " - " + DateTime.Now.ToString("HH:mm:ss"));
await Task.Delay(3000);
});
订阅者需要异步,但关键部分也是将 prefetchcount设置为1 。