为什么它一直给屏幕英寸尺寸错误?

时间:2017-04-07 05:30:54

标签: android screen-size android-screen

我想按英寸计算设备尺寸。我正在使用此代码,每次搜索都会出现。但问题是当我把设备4.5英寸我的答案在Android工作室是4.我尝试5.2英寸设备,我得到4.3英寸以及10.1英寸 - >答案是9.0。 那我怎样才能得到准确答案?

 DisplayMetrics dm = new DisplayMetrics();
    getWindowManager().getDefaultDisplay().getMetrics(dm);

    double wi=(double)dm.widthPixels/dm.xdpi;
    double hi=(double)dm.heightPixels/dm.ydpi;
    double x = Math.pow(wi,2);
    double y = Math.pow(hi,2);
    double screenInches = Math.sqrt(x+y);
    Log.e("hello"," "+screenInches);

4 个答案:

答案 0 :(得分:2)

您的代码存在问题,因为它没有考虑到

<强>动作条

<强>软键

屏幕方向

使用以下答案

 WindowManager windowManager = getWindowManager();
Display display = windowManager.getDefaultDisplay();
DisplayMetrics displayMetrics = new DisplayMetrics();
display.getMetrics(displayMetrics);

// since SDK_INT = 1;
mWidthPixels = displayMetrics.widthPixels;
mHeightPixels = displayMetrics.heightPixels;

// includes window decorations (statusbar bar/menu bar)
if (Build.VERSION.SDK_INT >= 14 && Build.VERSION.SDK_INT < 17)
{
    try
    {
        mWidthPixels = (Integer) Display.class.getMethod("getRawWidth").invoke(display);
        mHeightPixels = (Integer) Display.class.getMethod("getRawHeight").invoke(display);
    }
    catch (Exception ignored)
    {
    }
}

// includes window decorations (statusbar bar/menu bar)
if (Build.VERSION.SDK_INT >= 17)
{
    try
    {
        Point realSize = new Point();
        Display.class.getMethod("getRealSize", Point.class).invoke(display, realSize);
        mWidthPixels = realSize.x;
        mHeightPixels = realSize.y;
    }
    catch (Exception ignored)
    {
    }


 DisplayMetrics dm = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(dm);
double x = Math.pow(mWidthPixels/dm.xdpi,2);
double y = Math.pow(mHeightPixels/dm.ydpi,2);
double screenInches = Math.sqrt(x+y);
Log.d("debug","Screen inches : " + screenInches);

归功于him

答案 1 :(得分:1)

您可以使用 getResources()。getDisplayMetrics()

  

DisplayMetrics:描述有关a的一般信息的结构   显示,       例如它的大小,密度和字体缩放。

DisplayMetrics metrics = getResources().getDisplayMetrics();

    int width = metrics.widthPixels;
    int height = metrics.heightPixels;
    int dens = metrics.densityDpi;
    double wi = (double)width / (double)dens;
    double hi = (double)height / (double)dens;
    double x = Math.pow(wi, 2);
    double y = Math.pow(hi, 2);
    double screenInches = Math.sqrt(x+y);

    System.out.println("getSIZE"+screenInches);

有关详细信息,请访问 Android DisplayMetrics returns incorrect screen size.

答案 2 :(得分:0)

设备尺寸与屏幕尺寸不同,因为屏幕不会覆盖设备总尺寸

Android操作系统与设备尺寸无关,您无法以编程方式获取设备尺寸,只能获得屏幕尺寸

答案 3 :(得分:0)

只需稍加改动即可尝试

DisplayMetrics metrics = getResources().getDisplayMetrics();

int width = metrics.widthPixels;
int height = metrics.heightPixels;
int dens = metrics.densityDpi;
double wi = (double)width / (double)dens;
double hi = (double)height / (double)dens;
double x = Math.pow(wi, 2);
double y = Math.pow(hi, 2);
DecimalFormat df = new DecimalFormat("#.#");
df.setRoundingMode(RoundingMode.CEILING);
try {
double screenInches = Double.parseDouble(df.format(Math.sqrt(x+y)));

Log.e("hello"," "+screenInches);
} catch (NumberFormatException e) {

e.printStackTrace();

}
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