Question

user_input = "";
answer = "";

Array.greeting = ["hi", "hello"]
Array.names = ["john","james"]

user_input = document.getElementById('user_input').value.toLowerCase();
document.getElementById('text_input').innerHTML = user_input;

documnet.getElementById('say_something').innerHTML = say;
if(""){}
else{}
if(Array.greeting.includes(user_input) > 0){
    say = "Hello";
}
if(Array.names.includes(user_input) > 0){
    say = "User";
}

这就是我所理解的并且已经启动并运行了正确的输出，但我怎么能使用输入“hi john”并获得“Hello User”的输出而不将其烘焙成阵列？

Answer 1

让我们简化您的要求：你想检查数组中是否有任何元素＆＃34; arr＆＃34;包含字符串＆＃34; s＆＃34;。

的一部分

var check = function(arr, s) {
  for (var i = 0; i < arr.length; i++) {
    if (s.indexOf(arr[i]) > -1) {
      return true;
    }
  }
  return false;
}

Answer 2

你可以这样做：

＆＃13;

var greetings = ["hi", "hello"];
var names = ["john","james"];

submit.onclick = function () {
    // Split input into words, and convert that array to a Set for fast lookup
    var words = new Set(user_input.value.split(/\s+/));
    // Choose a greeting that is not among the input words.
    // If all of them occur in the input, take the first greeting word
    var greeting = greetings.find( greeting => !words.has(greeting)) || greetings[0]; 
    // Choose a name that is not among the input words (or take the first)
    var name = names.find( name => !words.has(name)) || names[0];
    // Output with textContent (not innerHTML!)
    text_input.textContent = user_input.value;
    say_something.textContent = greeting + ' ' + name;
}

＆＃13;

Input: <input id="user_input"><button id="submit">Submit</button><br>

You said: <span id="text_input"></span><br>
Reply: <span id="say_something"></span>

＆＃13;

显然，当你同时输入＆＃34; hi＆＃34;并且＆＃34;你好＆＃34;，代码将找不到要使用的问候语。在这种情况下，它使用数组中的第一个问候语（＆＃34; hi＆＃34;）。同样的原则适用于名称。

如何检查字符串的一部分是否在数组中？

2 个答案: