Question

我有下面的表格和代码，试图在我的网络应用上建立一个跟随和取消关注的朋友关系。问题在于，当我运行此代码时：

按钮仍然是＆＃34;关注＆＃34;并且＆＃34;禁用＆＃34;在Firefox，Chrome，Safari上，它显示＆＃34;取消关注＆＃34;在Torch浏览器上。当用户A是登录用户时，会发生这种情况，访问用户-B的个人资料页面
即使在Torch浏览器上，当我点击＆＃34;取消关注＆＃34;或＆＃34;关注＆＃34;，没有任何反应 - 按钮不会在关注和取消关注之间切换，我的数据库也不会更新。
注意：我手动输入了＆＃34;关注＆＃34;数据库表，因为follow和unfollow按钮不会更新数据库。

TABLENAME - 关注

id     user1    user2     countrycode mobile       
1      USER-A   USER-B    234         08023334567

TABLENAME - 用户

id      username    password     mobile             activated                
 1       USER-A                   08023334567         1

 2       USER-B                   08034448987         1

user.php

<?php
$following = false;
$login_username = "USER-A";
$u = "USER-B";
$user_ok = true;

if($u != $login_username && $user_ok == true){
    $following_check = "SELECT id FROM follows WHERE user1='$login_username' AND user2='$u' LIMIT 1";
    if(mysqli_num_rows(mysqli_query($db_connect, $following_check)) > 0){
        $following = true;  
    }
}
?><?php
$follow_button = '<button disabled>Follow</button>';

//LOGIC FOR FOLLOW BUTTON
if($following == true){
    $follow_button = '<button onclick="followToggle(\'unfollow\',\''.$u.'\',\'followBtn\')">Unfollow</button>';
} else if($user_ok == true && $u != $log_username && $following == false) {
    $follow_button = '<button onclick="followToggle(\'follow\',\''.$u.'\',\'followBtn\')">Follow</button>';
} 
?>

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title><?php echo $u; ?></title>
<link rel="icon" href="favicon.ico" type="image/x-icon">
<link rel="stylesheet" href="style/style.css">
<meta name="viewport" content="width=device-width, initial-scale=1.0">

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.0/jquery.min.js"></script>
<script src="js/ajax.js"></script>
<script>
function followToggle(type, user, elem) {
    var conf = confirm("Press OK to confirm the '" + type + "' action for user <?php echo $u; ?>.");
    if (conf != true) {
        return false;
    }
    _(elem).innerHTML = 'please wait ...';
    var ajax = ajaxObj("POST", "follow_system.php");
    ajax.onreadystatechange = function() {
        if (ajaxReturn(ajax) == true) {
            if (ajax.responseText == "follow_ok") {
                _(elem).innerHTML = '<button onclick="followToggle(\'unfollow\',\'<?php echo $u; ?>\',\'friendBtn\')">Unfollow</button>';
            } else if (ajax.responseText == "unfollow_ok") {
                _(elem).innerHTML = '<button onclick="followToggle(\'follow\',\'<?php echo $u; ?>\',\'friendBtn\')">Follow</button>';
            } else {
                alert(ajax.responseText);
                _(elem).innerHTML = 'Try again later';
            }
        }
    }
    ajax.send("type=" + type + "&user=" + user);
}
</script>
</head>
<body>
<div id="PageMiddle">

    <p><span id="friendBtn"><?php echo $follow_button; ?></p>

</div>

</body>
</html>

follow_system.php

 <?php
$user_ok = true;
$login_username != "";
    if($user_ok != true || $login_username == "") {
        exit();
    }
    ?><?php
    if (isset($_POST['type']) && isset($_POST['user'])){
        $user = preg_replace('#[^a-z0-9._@]#i', '', $_POST['user']);
            $sql = "SELECT COUNT(id) FROM users WHERE username='$user' AND activated='1' LIMIT 1";
            $query = mysqli_query($db_connect, $sql);
            $exist_count = mysqli_fetch_row($query);
            if($exist_count[0] < 1){
                mysqli_close($db_connect);
                echo "$user does not exist.";
                exit();
            }
        if($_POST['type'] == "follow"){
                $sql = "INSERT INTO follows(user1, user2, countrycode, mobile) VALUES('$login_username','$user','$countrycode','$mobile')";
                $query = mysqli_query($db_connect, $sql);
                mysqli_close($db_connect);
                echo "follow_ok";
                exit();
            } else if($_POST['type'] == "unfollow"){
                $sql = "DELETE FROM follows WHERE user1='$login_username' AND user2='$user' AND countrycode='$countrycode' AND mobile='$mobile'";
                $query = mysqli_query($db_connect, $sql);
                mysqli_close($db_connect);
                echo "unfollow_ok";
                exit();
            } 
        }

    ?>

关注和取消关注系统 - 不确定我的代码有什么问题

0 个答案: