Question

我在文本文件中有一些数据格式如下：

A.B.C=12
A.B.D=13
A.C.D=14

并且需要将它放入树视图控件中，使其看起来像这样：

两端的标签值应与文本中的标签值相同，即。 C = 12.

我尝试过的大部分内容都围绕着在每一行上使用foreach循环，然后将字符串拆分为'。'和'='并循环遍历这些，但我无法获得它可以工作。

非常感谢任何帮助......

Answer 1

这是解决问题的方法之一。评论在代码中。适用于您的样本数据，但我不能保证它在其他一些情况下可以使用：）

主要方法是PopulateTreeView()，因此请在表格Load事件中调用它。此外，还有辅助方法FindNode，用于搜索第一级节点以查找是否存在提供文本的节点。

如果您还有其他问题，请随时提出。

private void PopulateTreeView()
{
    //read from file
    var lines = File.ReadAllLines(@"c:\temp\tree.txt");
    //go through all the lines
    foreach (string line in lines)
    {
        //split by dot to get nodes names
        var nodeNames = line.Split('.');
        //TreeNode to remember node level
        TreeNode lastNode = null;

        //iterate through all node names
        foreach (string nodeName in nodeNames)
        {
            //values for name and tag (tag is empty string by default)
            string name = nodeName;
            string tagValue = string.Empty;
            //if node is in format "name=value", change default values of name and tag value. If not, 
            if (nodeName.Contains("="))
            {
                name = nodeName.Split('=')[0];
                tagValue = nodeName.Split('=')[1];
            }

            //var used for finding existing node
            TreeNode existingNode = null;
            //new node to add to tree
            TreeNode newNode = new TreeNode(name);
            newNode.Tag = tagValue;
            //collection of subnodes to search for node name (to check if node exists)
            //in first pass, that collection is collection of treeView's nodes (first level)
            TreeNodeCollection nodesCollection = treeView1.Nodes;

            //with first pass, this will be null, but in every other, this will hold last added node.
            if (lastNode != null)
            {
                nodesCollection = lastNode.Nodes;
            }

            //look into collection if node is already there (method checks only first level of node collection)
            existingNode = FindNode(nodesCollection, name);
            //node is found? In that case, skip it but mark it as last "added"
            if (existingNode != null)
            {
                lastNode = existingNode;
                continue;
            }
            else //not found so add it to collection and mark node as last added.
            {
                nodesCollection.Add(newNode);
                lastNode = newNode;
            }
        }
    }

    treeView1.ExpandAll();
}

private TreeNode FindNode(TreeNodeCollection nodeCollectionToSearch, string nodeText)
{
    var nodesToSearch = nodeCollectionToSearch.Cast<TreeNode>();
    var foundNode = nodesToSearch.FirstOrDefault(n => n.Text == nodeText);
    return foundNode;
}

从具有值的路径列表填充TreeView

1 个答案: