Question

我正在尝试创建一个用户可以搜索图书标题的搜索。 “书籍”表中有一个名为“title”的字段。

然而，如果我做dd（$ books）;我明白了：

Collection {#667 ▼
  #items: []
}

如果我做dd（$ searchTerms）;输出似乎是正确的

这是我的控制器：

    function search()
    {
        $books = Book::all();
        return view('layouts/search',['books' => $books]);
    }
        function details() {
            $searchTerms = explode(' ', \Request::input('book')); 
            $books = Book::where(function($q) use($searchTerms) {
            foreach ($searchTerms as $book) {
             $q->orWhere('title', '%'.$book.'%');
            }
        })->get();
            dd($books);
        return view('layouts/details', compact('books'));
}

搜索刀片：

@extends('layouts.master')

@section('title')

@section('content')
    <h1>Search for books</h1>
    <form action="{{url('details')}}" method="POST">
    {{ csrf_field() }}
        <div>
            <input type='text'  name='book' placeholder='Enter any character' />
        </div>
    <input type="submit" name="submitBtn" value="Search">
    </form>
@endsection

详情刀片：

@extends('layouts.master')

@section('title')

@section('content')
    <h1>User Details</h1>
      <form>
      <p>
    <ul>
      @foreach ($books as $book)
    <a href=  "{{url('reader/'.$book->title)}}">
      {{$book->title}}</a>
      </p>
</form>
@endforeach
    </ul>
@endsection

Answer 1

您忘记告诉雄辩的构建者您的OR应该LIKE作为运营商：

$q->orWhere('title', 'like', '%'.$book.'%');

Answer 2

请将详细信息的功能更改为

function details(Request $request) {
        $searchTerms = $request->book; 
        $books = Book::where(function($q) use($searchTerms) {
        foreach ($searchTerms as $book) {
         $q->orWhere('title', '%'.$book.'%');
        }
    })->get();
        dd($books);
    return view('layouts/details', compact('books'));
}

Laravel搜索没有返回任何结果

2 个答案: