如何从XML文件中提取元素？

Question

我有以下简单的XML片段。如果我想提取'EntityFriendlyName'属性，T-SQL会是什么样子？

<SimpleRuleValue xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <EntityId>0</EntityId>
    <EntityFriendlyName>ALine</EntityFriendlyName>
</SimpleRuleValue>

Answer 1

这将是这样的：

SELECT CAST(X.SomeXML AS XML).value('(SimpleRuleValue/EntityFriendlyName)[1]','nvarchar(1000)') AS EntityFriendlyName
FROM XmlSource X

编辑： A little more information.

Answer 2

这是一种方式：

declare @x xml

set @x = '<SimpleRuleValue xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
              <EntityId>0</EntityId>
              <EntityFriendlyName>ALine</EntityFriendlyName>
          </SimpleRuleValue>'

select @x.query('data(SimpleRuleValue/EntityFriendlyName)')