Question

我非常感谢我对java代码的一些帮助。我正在使用ArrayLists来存储用户喜欢的车辆类型。因此他们将输入车辆，直到他们输入“退出”以退出循环。然后它将打印数组列表。现在，它只是阅读所有其他输入。根据输入的输入数量，用户可能必须在打印结果之前键入“退出”两次。非常感谢任何帮助，谢谢！

package bacaCCh6Sec8;
import java.util.ArrayList;
import java.util.Scanner;
public class BacaCCh6Sec8 {
  public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    ArrayList<String> vehicles = new ArrayList<>();
    boolean done = false; 
    final String EXIT = "Exit";
    System.out.printf("Enter your favorite vehicles.\n");
    System.out.printf("Type Exit after you have input all your vehicles.\n");
    do {
        String input = in.next();
        if (!input.equals(EXIT)) {
            vehicles.add(in.next());
        } else {
            done = true;
        } // end If
    } while (!done); // End Do While
    System.out.printf("Your favorite vehicles are %s.\n" , vehicles);

    } // End Main
} // End Class

Answer 1

用户可能必须输入＆＃34;退出＆＃34;在打印结果之前两次出

问题是您要两次调用docker exec -it <container_id> bash方法，因此用户必须输入两次值。解决方案是简单地使用您从第一个next()方法获得的值，而不是丢弃它。

next()

Answer 2

.next()的每次调用实际上都会读取输入。因此，如果您拨打.next()两次，它会读两行。要将更改vehicles.add(in.next());更正为vehicles.add(input);

Answer 3

    public static void main(String[] args) {
            Scanner in = new Scanner(System.in);
            ArrayList<String> vehicles = new ArrayList<>();
            boolean done = false; 
            final String EXIT = "Exit";
            System.out.printf("Enter your favorite vehicles.\n");
            System.out.printf("Type Exit after you have input all your vehicles.\n");
            do {
                String word = in.next();
                if(word.equalsIgnoreCase("exit")) break;

                vehicles.add(word);

            } while (!done); // End Do While
            System.out.printf("Your favorite vehicles are %s.\n" , vehicles);
     }
}

不是我最好的代码，但有帮助

Enter your favorite vehicles.
Type Exit after you have input all your vehicles.
hola
mundo
exit
Your favorite vehicles are [hola, mundo].

Arraylist用户输入

3 个答案: