Question

我的代码目前在抓取过程中创建了以下输出：https://pastebin.com/pUcCdbMn。

我想在listing-title中获取文本，即

<h2 class="listing-title"><a class="listing-fpa-link" href="...">Vauxhall Astra 1.6i 16V Design 5dr Hatchback</a></h2>

返回沃克斯豪尔Astra 1.6i 16V设计5dr两厢

listing-key-specs，即

<ul class="listing-key-specs">
<li>2015
(65 reg)</li>
<li>Hatchback</li>
<li>14,304 miles</li>
<li>Manual</li>
<li>1.6L</li>
<li>Petrol</li>
</ul>

将 2015（65 reg），两厢车，＆＃34; 14,304英里＆＃34;，手动，1.6L，汽油全部作为单独变量返回。

我怎样才能做到这一点？当我尝试提取列表标题时，我的代码当前返回None：

for page in range(1, 3):
    page_count = str(page)
    if page is 1:
        url = "http://www.autotrader.co.uk/car-search?sort=sponsored&radius=1500&postcode=se218qe&onesearchad=Used&onesearchad=Nearly%20New&onesearchad=New"
    else:
        url = "http://www.autotrader.co.uk/car-search?sort=sponsored&radius=1500&postcode=se218qe&onesearchad=Used&onesearchad=Nearly%20New&onesearchad=New&page=" + page_count
    browser.get(url)
    soup = BeautifulSoup(browser.page_source, "html.parser")
    cars = soup.find_all('li', {'class': 'search-page__result'})
    cars_count = len(cars)
    print 'Processing ' + str(cars_count) + ' cars found on page ' + page_count

    # Loop through cars on page
    for car in cars:
        car_name = car.find('h2 ', {'class': 'listing-title'})
        print car_name

Answer 1

您在标记名称后面有这个额外的空格：

car_name = car.find('h2 ', {'class': 'listing-title'})
                 # HERE^

删除它，它应该按原样开始工作。

请注意，要获取标题文本，请使用get_text()方法：

print(car_name.get_text(strip=True))

您也可以将.find()替换为.select_one()：

car_name = car.find('h2.listing-title')

我还会让脚本更可靠，explicitly wait使搜索结果在读取页面源并传递给它以进一步解析之前出现：

from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.wait import WebDriverWait

# ...
browser.get(url)

wait = WebDriverWait(browser, 10)
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, ".search-page__result .listing-title")))

soup = BeautifulSoup(browser.page_source, "html.parser")

＆＃34;无＆＃34;在刮擦期间返回

1 个答案: