Question

如果已经处理了观察者，则RxJava2 Single内部抛出的RuntimeException不会被捕获，也不会被发送到Observer的onError（）方法。
我理解调用CompositeDisposable.dispose（）意味着我的订阅者的onSuccess或onError方法不会被调用，但是也不应该忽略该异常？而是应用程序崩溃，因为没有捕获到RuntimeException。

这是Single，带注释的行可以抛出RuntimeException，如果在调用.dispose（）方法之前抛出异常，它会被捕获并且错误被发送给订阅者，但是如果异常在调用.dispose（）后，应用程序崩溃了。

public Single<Submission> getSubmission(final String threadId, final CommentSort sort) {
        return Single.create(new SingleOnSubscribe<Submission>() {
            @Override
            public void subscribe(SingleEmitter<Submission> e) throws Exception {
                // some irrelevant code

                try {
                    submission = reddit.getSubmission(sr); // Can throw RuntimeException
                    e.onSuccess(submission);
                } catch (Exception ex) {
                    e.onError(ex);
                }
            }
        });
    }

我订阅的代码：

disposables.add(someCompletable
                .andThen(service.getSubmission(threadId, CommentSort.HOT))
                .subscribeOn(schedulerProvider.io())
                .observeOn(schedulerProvider.ui())
                .subscribeWith(new DisposableSingleObserver<Submission>() {
                    @Override
                    public void onSuccess(Submission submission) {
                        // Handle result
                    }

                    @Override
                    public void onError(Throwable e) {
                        // Handle error
                    }
                })
        );

Stacktrace：

E/AndroidRuntime: FATAL EXCEPTION: RxCachedThreadScheduler-2
Process: com.gmail.jorgegilcavazos.ballislife.debug, PID: 15242
java.lang.RuntimeException: Unable to parse JSON: [{"kind": "Listing", "data": {"modhash": null, "children": [{"kind": "t3", "data
at net.dean.jraw.util.JrawUtils.fromString(JrawUtils.java:182)
at net.dean.jraw.http.RestResponse.<init>(RestResponse.java:64) 
at net.dean.jraw.http.OkHttpAdapter.execute(OkHttpAdapter.java:81)
at net.dean.jraw.http.RestClient.execute(RestClient.java:120)
at net.dean.jraw.RedditClient.execute(RedditClient.java:143)
at net.dean.jraw.RedditClient.execute(RedditClient.java:137)
at net.dean.jraw.RedditClient.getSubmission(RedditClient.java:287)
at com.gmail.jorgegilcavazos.ballislife.network.API.RedditService$10.subscribe(RedditService.java:311)
at io.reactivex.internal.operators.single.SingleCreate.subscribeActual(SingleCreate.java:39)
at io.reactivex.Single.subscribe(Single.java:2656)
at io.reactivex.internal.operators.single.SingleDelayWithCompletable$OtherObserver.onComplete(SingleDelayWithCompletable.java:70)
at io.reactivex.internal.disposables.EmptyDisposable.complete(EmptyDisposable.java:67)
at io.reactivex.internal.operators.completable.CompletableEmpty.subscribeActual(CompletableEmpty.java:27)
at io.reactivex.Completable.subscribe(Completable.java:1592)
at io.reactivex.internal.operators.single.SingleDelayWithCompletable.subscribeActual(SingleDelayWithCompletable.java:36)
at io.reactivex.Single.subscribe(Single.java:2656)

Answer 1

找到答案：

RxJava 2的设计使得不会丢失任何错误。因此，当序列结束或被取消时，发射器无处发送错误，因此它被路由到RxJavaPlugins.onError。与1.x不同，2.x默认情况下调用Thread.currentThread().getUncaughtExceptionHandler().uncaughtException()会导致Android应用崩溃。

Source
Similar stackoverflow question

在我的情况下，由于订户已被处理，我不再关心发射器可能抛出的错误，因此发射器应在调用onError()

之前检查它是否已被处理掉

try {
      Submission submission = redditClient.getSubmission(sr);
      e.onSuccess(submission);
} catch (Exception ex) {
      if (!e.isDisposed()) {
           e.onError(ex);
      }
}

抛出RuntimeException并在RxJava2处理后没有被捕获

1 个答案: