Question

我有一个数组。我尝试分析每个元素（每个元素是一个字符）并比较每个元素是否单独等于另一个字符，如下所示：

（以下代码不正确，仅供说明）

let array = ["5","a","5","8","l","j"]
var finalString = ""
for i in array {
    if array[i] = ["^0-9"] {
        //Compares if the element in position i is equal to a number between 0 - 9
        finalString + "1 " //or do something else
    } else if array[i] = ["^a-z"] {
        //Compares if the element in position i is equal to a character between a - z
        finalString + "2 " //or do something else
    }
}
print(finalString)
//Expected output
// 1 2 1 1 2 2

我希望我的问题的解释清楚。

Answer 1

我想了解更多有关可能的输入值的信息。

let array = ["5","a","5","8","l","j"]

let finalString = array.reduce("") { result, character in
    switch character {
    case "0"..."9": return result.appending("1 ")
    case "a"..."z": return result.appending("2 ")
    default: assertionFailure("\(character) is unexpected input"); return result
    }
}

print(finalString)

Answer 2

你有几个问题。以下代码清除了这些问题，并使用CharacterSet查看数组元素是否包含数字或字母。

let array = ["5","a","5","8","l","j"]
var finalString = ""
for str in array {
    if str.rangeOfCharacter(from: .decimalDigits) != nil {
        //Compares if the string contains any digits
        finalString += "1 " //or do something else
    } else if str.rangeOfCharacter(from: .letters) != nil {
        //Compares if the string contains any letters
        finalString += "2 " //or do something else
    } else {
        finalString += "0 " //or do something else
    }
}
print("Res: \(finalString)")

输出：

分辨率：1 2 1 1 2 2

这些特定检查与您在代码中提到的检查略有不同，但对于您的示例，它会给出相同的结果。

如果您只想接受0-9或a-z，则需要更新正在使用的特定字符集。

如何迭代数组并将每个元素与Swift中的其他元素进行比较

2 个答案: